The sum of the exterior angles of a polygon is:
360°
The sum of the exterior angles of any convex polygon, taken one at each vertex, is always 360°, regardless of the number of sides.
This is because as one walks around the polygon along its boundary, the total turning at each corner is one full revolution.
Quick check (square): a square has 4 exterior angles of 90° each → \(4 \times 90^\circ = 360^\circ\). ✓
Quick check (equilateral triangle): 3 exterior angles of 120° each → \(3 \times 120^\circ = 360^\circ\). ✓
Hence the answer is 360°.
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In ΔABC, ∠A = 90°, AD ┴ BC and AD = BD = 2 cm. The length of CD is
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If the angles of a triangle are in the ratio of 2:3:4, then the difference of the measure of greatest angle and smallest angle is
In ΔABC, ∠A = 90°, AD ┴ BC and AD = BD = 2 cm. The length of CD is
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I. Rectangle
II. Isosceles triangle