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Question

The speed of boat in still water is 6 km/hr and speed of stream is 3 km/hr. Calculate the time taken to cover 27 km distance downstream and returning on it upstream.

This question was previously asked in
ESIC UDC Mains MBT (30 Apr 2022)
The correct answer is

12 hr

This problem involves calculating the total time taken by a boat to travel a certain distance downstream and then return the same distance upstream. We are given the speed of the boat in still water and the speed of the stream.

Understanding Speeds in Water

When a boat travels in water, its speed relative to the bank depends on the direction of travel relative to the stream's current.

  • Downstream Travel: The boat travels in the same direction as the stream. The effective speed is the sum of the boat's speed in still water and the stream's speed.
  • Upstream Travel: The boat travels against the direction of the stream. The effective speed is the difference between the boat's speed in still water and the stream's speed.

Given Information

We are provided with the following details:

  • Speed of the boat in still water ($S_b$) = 6 km/hr
  • Speed of the stream ($S_s$) = 3 km/hr
  • Distance ($D$) = 27 km (for both downstream and upstream journeys)

Calculating Downstream Speed

The speed of the boat when traveling downstream ($S_{down}$) is calculated by adding the speed of the boat in still water to the speed of the stream:

$$ S_{down} = S_b + S_s $$

Substituting the given values:

$$ S_{down} = 6 \text{ km/hr} + 3 \text{ km/hr} = 9 \text{ km/hr} $$

Calculating Time Taken Downstream

The time taken to cover a distance is given by the formula: Time = Distance / Speed.

Time taken downstream ($T_{down}$) is:

$$ T_{down} = \frac{D}{S_{down}} $$

Substituting the values:

$$ T_{down} = \frac{27 \text{ km}}{9 \text{ km/hr}} = 3 \text{ hr} $$

Calculating Upstream Speed

The speed of the boat when traveling upstream ($S_{up}$) is calculated by subtracting the speed of the stream from the speed of the boat in still water:

$$ S_{up} = S_b - S_s $$

Substituting the given values:

$$ S_{up} = 6 \text{ km/hr} - 3 \text{ km/hr} = 3 \text{ km/hr} $$

Calculating Time Taken Upstream

Similarly, the time taken upstream ($T_{up}$) is:

$$ T_{up} = \frac{D}{S_{up}} $$

Substituting the values:

$$ T_{up} = \frac{27 \text{ km}}{3 \text{ km/hr}} = 9 \text{ hr} $$

Calculating Total Time

The total time taken for the entire journey (downstream and upstream) is the sum of the time taken for each part:

$$ T_{total} = T_{down} + T_{up} $$

$$ T_{total} = 3 \text{ hr} + 9 \text{ hr} = 12 \text{ hr} $$

Summary of Calculations

Here's a summary of the calculated speeds and times:

Journey Type Speed (km/hr) Time Taken (hr)
Downstream 9 3
Upstream 3 9
Total - 12

Therefore, the total time taken to cover 27 km distance downstream and return on it upstream is 12 hours.

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Important Questions from Speed Time and Distance

  1. A journey of 900 km is completed in 11 h. If two-fifth of the journey is completed at the speed of 60 km/h, at what speed (in km/h) is the remaining journey completed?

  2. A car starts from point A towards point B, travelling at the speed of 20 km/h. 1 \(\frac{1}{2}\) hours later, another car starts from point A and travelling at the speed of 30 km/h and reaches 2 \(\frac{1}{2}\) hours before the first car. Find the distance between A and B.

  3. A bus covered a distance of 162 km. If speed of this bus is 15 m/s, then what will be the time taken ?

  4. An athlete runs an 800 m race in 96 seconds. His speed (in km / h) is:

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