The Speed of a car travelling on a straight road is listed below at successive intervals of 1 s: Time (s) Speed (m / s) 0 0 1 2 2 4 3 6 4 8 Which of the following is/are correct? The car travels: Select the correct answer using the code given belowTime (s)
1, 2 & 3
The question provides us with the speed of a car recorded at successive 1-second intervals and asks us to evaluate several statements about its motion. We need to analyze the given time and speed data to determine which statements are correct.
Let's first look at the data provided:
| Time (s) | Speed (m/s) |
|---|---|
| 0 | 0 |
| 1 | 2 |
| 2 | 4 |
| 3 | 6 |
| 4 | 8 |
From this table, we can see how the car's speed changes over time.
The first statement says the car travels with a uniform acceleration of 2 m/s2. Acceleration is the rate of change of speed. To check if the acceleration is uniform, we calculate the change in speed over each 1-second interval:
Since the acceleration is constant at 2 m/s2 over each interval, the car has a uniform acceleration of 2 m/s2. So, statement 1 is correct.
The second statement says the car travels 16 m in 4 s. Since the car starts from rest (speed is 0 m/s at t=0) and moves with uniform acceleration, we can use the kinematic equation for displacement:
\[ s = ut + \frac{1}{2}at^2 \]where:
From the data and statement 1, we know:
Plugging these values into the equation:
\[ s = (0 \, \text{m/s})(4 \, \text{s}) + \frac{1}{2}(2 \, \text{m/s}^2)(4 \, \text{s})^2 \]
\[ s = 0 + \frac{1}{2}(2)(16) \, \text{m} \]
\[ s = 16 \, \text{m} \]
So, the car travels 16 m in 4 seconds. Statement 2 is correct.
The third statement says the car travels with an average speed of 4 m/s. Average speed is defined as the total distance traveled divided by the total time taken.
\[ \text{Average speed} = \frac{\text{Total distance}}{\text{Total time}} = \frac{16 \, \text{m}}{4 \, \text{s}} = 4 \, \text{m/s} \]
Alternatively, for motion with uniform acceleration, the average speed over a time interval is also the average of the initial and final speeds during that interval.
\[ \text{Average speed} = \frac{\text{Initial speed} + \text{Final speed}}{2} = \frac{0 \, \text{m/s} + 8 \, \text{m/s}}{2} = \frac{8 \, \text{m/s}}{2} = 4 \, \text{m/s} \]
So, the average speed of the car over 4 seconds is 4 m/s. Statement 3 is correct.
Based on our analysis, all three statements are correct:
Therefore, the correct option should include all three statements.
| Concept | Definition | Formula (for uniform acceleration) |
|---|---|---|
| Speed | Magnitude of velocity (rate of change of distance) | Varies with time, \(v = u + at\) |
| Acceleration | Rate of change of speed/velocity | Constant, \(a = \frac{v-u}{t}\) |
| Distance/Displacement | Change in position | \(s = ut + \frac{1}{2}at^2\) or \(v^2 = u^2 + 2as\) |
| Average Speed | Total distance / Total time | \(\frac{s}{t}\) or \(\frac{u+v}{2}\) (for uniform acceleration) |
When an object moves with uniform acceleration, its speed changes by the same amount in every equal interval of time. This type of motion is governed by a set of equations called kinematic equations, which relate displacement (\(s\)), initial velocity (\(u\)), final velocity (\(v\)), acceleration (\(a\)), and time (\(t\)). The equations used in this solution are derived from these principles. Understanding uniform acceleration is fundamental to solving many problems in mechanics.
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