In a balanced transportation problem with \(m\) sources and \(n\) destinations, a basic feasible solution has fewer than \(m+n-1\) strictly positive allocations. What is this situation called?
Degeneracy
This is degeneracy. A transportation basis has \(m+n-1\) basic variables. If at least one is zero, there are fewer strictly positive allocations. A cell being simultaneously cheapest in its row and column does not by itself establish degeneracy.
Match the symbols used in preparation of process chart given in List - I with their description in List - II:
| List - I Symbols used in process chart | List - II Description |
|---|---|
| A. $\nabla$ | I. Movement from place to place |
| B. $\square$ | II. Delay |
| C. $\bigcirc$ | III. Inspection for quantity and quality |
D. ![]() | IV. Movement and Operation |
Choose the correct answer from the options given below :