The real variables $x, y, z$ and the real constants $p, q, r $ satisfy
$\frac{x}{pq - r^2} = \frac{y}{qr - p^2} = \frac{z}{rp - q^2}$
Given the denominators are non-zero, the value of $px + qy + rz$ is
We are given the proportion:
$ \frac{x}{pq - r^2} = \frac{y}{qr - p^2} = \frac{z}{rp - q^2} $
We need to find the value of the expression $px + qy + rz$, given that the denominators are non-zero.
Let $k$ be the common value of the ratios:
$ k = \frac{x}{pq - r^2} = \frac{y}{qr - p^2} = \frac{z}{rp - q^2} $
From this, we can express $x$, $y$, and $z$ in terms of $k$ and the denominators:
Now, substitute these expressions for $x$, $y$, and $z$ into the target expression $px + qy + rz$:
$ px + qy + rz = p[k(pq - r^2)] + q[k(qr - p^2)] + r[k(rp - q^2)] $
Factor out the common term $k$:
$ px + qy + rz = k [ p(pq - r^2) + q(qr - p^2) + r(rp - q^2) ] $
Distribute the constants $p$, $q$, and $r$ inside the brackets:
$ px + qy + rz = k [ (p^2q - pr^2) + (q^2r - qp^2) + (r^2p - rq^2) ] $
Rearrange the terms within the brackets to group like terms:
$ px + qy + rz = k [ (p^2q - qp^2) + (q^2r - rq^2) + (r^2p - pr^2) ] $
Simplify the grouped terms:
$ px + qy + rz = k [ 0 + 0 + 0 ] $
$ px + qy + rz = k \times 0 $
$ px + qy + rz = 0 $
Therefore, the value of the expression $px + qy + rz$ is 0.
The relationship between two variables $x$ and $y$ is given by $x + py + q = 0$ and is shown in the figure. Find the values of $p$ and $q$.
Note: The figure shown is representative.
The complex function
$e^{-\left(\frac{2}{z-1}\right)}$
has __________________
Consider two matrices: $P = \begin{bmatrix} 1 & 2 \\ 0 & 1 \end{bmatrix}$ and $Q = \begin{bmatrix} 1 & 0 \\ 1 & 0 \end{bmatrix}$.
Which of the following statement is/are true?