The slope ($m$) of a straight line passing through two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula:
$ m = \frac{y_2 - y_1}{x_2 - x_1} $
We are given two points, $(4, p)$ and $(0, q)$, and the slope $m = \frac{3}{4}$. Let $(x_1, y_1) = (4, p)$ and $(x_2, y_2) = (0, q)$.
Substitute these values into the slope formula:
$ \frac{3}{4} = \frac{q - p}{0 - 4} $
Simplify the denominator:
$ \frac{3}{4} = \frac{q - p}{-4} $
To solve for $(q - p)$, multiply both sides by $-4$:
$ (q - p) = \frac{3}{4} \times (-4) $
$ q - p = -3 $
The question asks for the value of $(p - q)$. Since $(q - p) = -3$, we can find $(p - q)$ by multiplying by $-1$:
$ p - q = -(q - p) $
$ p - q = -(-3) $
$ p - q = 3 $
Therefore, the value of $(p – q)$ is $3$. The correct option is C.
Given $f(x, y) = x^2 - 2xy + y^2$
The complete contour of the equation $f(x, y) = 1$ is described by the option(s) ___.