The ratio of the incomes of two employees is 7 : 4, and the ratio of their expenditures is 3 : 1. If each of them manages to save ₹4,800 per month, find the sum of their monthly incomes (in ₹).
21120
This problem involves the concept of ratios and how they relate to income, expenditure, and savings. We are given the ratio of the incomes of two employees and the ratio of their expenditures. We also know the exact amount each employee saves per month. Our goal is to find the total of their monthly incomes.
The fundamental relationship we will use is:
Savings = Income - Expenditure
Let the ratio of incomes be \(7x : 4x\). So, the monthly income of the first employee is \(7x\) and the monthly income of the second employee is \(4x\).
Let the ratio of expenditures be \(3y : 1y\). So, the monthly expenditure of the first employee is \(3y\) and the monthly expenditure of the second employee is \(y\).
We are told that each employee saves ₹4,800 per month.
Using the Savings = Income - Expenditure relationship, we can write two equations based on the information for each employee:
We now have a system of two linear equations with two variables, \(x\) and \(y\).
We can solve this system of equations using either substitution or elimination method. Let's use the substitution method.
From the second equation (\(4x - y = 4800\)), we can express \(y\) in terms of \(x\):
\(y = 4x - 4800\)
Now, substitute this expression for \(y\) into the first equation (\(7x - 3y = 4800\)):
\(7x - 3(4x - 4800) = 4800\)
Distribute the -3:
\(7x - 12x + 14400 = 4800\)
Combine the \(x\) terms:
\(-5x + 14400 = 4800\)
Subtract 14400 from both sides:
\(-5x = 4800 - 14400\)
\(-5x = -9600\)
Divide by -5 to find the value of \(x\):
\(x = \frac{-9600}{-5}\)
\(x = 1920\)
Now that we have the value of \(x\), we can find the monthly income of each employee using the income ratio \(7x : 4x\).
Let's calculate these values:
The question asks for the sum of their monthly incomes. This is the sum of the two incomes we just calculated.
Sum of incomes = First employee's income + Second employee's income
Sum of incomes = \(13440 + 7680\)
Sum of incomes = \(21120\)
Alternatively, since the incomes are \(7x\) and \(4x\), their sum is \(7x + 4x = 11x\). We found \(x = 1920\), so the sum of incomes is:
Sum of incomes = \(11 \times 1920 = 21120\)
The sum of their monthly incomes is ₹21,120.
| Item | Ratio | Variable Representation | Calculated Amount (Using x=1920, y=2880) |
|---|---|---|---|
| Employee 1 Income | 7 | \(7x\) | \(7 \times 1920 = 13440\) |
| Employee 2 Income | 4 | \(4x\) | \(4 \times 1920 = 7680\) |
| Employee 1 Expenditure | 3 | \(3y\) | \(3 \times 2880 = 8640\) |
| Employee 2 Expenditure | 1 | \(y\) | \(1 \times 2880 = 2880\) |
| Employee 1 Savings | - | \(7x - 3y\) | \(13440 - 8640 = 4800\) |
| Employee 2 Savings | - | \(4x - y\) | \(7680 - 2880 = 4800\) |
| Sum of Incomes | 7+4=11 | \(11x\) | \(11 \times 1920 = 21120\) |
| Concept | Definition/Formula |
|---|---|
| Income | Money received, usually regularly, for work or through investments. Represented as a ratio \(7x:4x\). |
| Expenditure | Money spent on goods and services. Represented as a ratio \(3y:y\). |
| Savings | The part of income that is not spent. Calculated as Savings = Income - Expenditure. Given as ₹4,800 for each employee. |
| Ratio | A comparison of two quantities of the same kind, expressed as \(a:b\) or \(\frac{a}{b}\). Used here to represent the relative scales of incomes and expenditures. |
| System of Linear Equations | A set of two or more linear equations involving the same variables. We used this to solve for \(x\) and \(y\). |
Ratio and proportion problems often require setting up algebraic equations. Here are some key points:
Understanding these basic concepts of ratios and algebra is crucial for solving problems like this income and expenditure ratio question.
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