The pu parameters for a 300 MVA machine on its own base are inertia M = 10 pu and reactance X = 4 pu. The pu values of inertia and reactance on 50 MVA common base, respectively, will be:
60, 0.67
This problem requires converting the per unit (pu) values of inertia and reactance for an electrical machine from its original base rating (300 MVA) to a new common base rating (50 MVA). Understanding how these values change with the base power is crucial in power system analysis.
We are provided with the following information for the machine:
Per unit values simplify calculations in power systems by normalizing quantities relative to specified base values (usually power and voltage). When the base power is changed, the pu values of certain parameters must be adjusted:
Using the inertia conversion formula:
$$ M_2 = M_1 \times \frac{S_{base1}}{S_{base2}} $$
Substitute the given values:
$$ M_2 = 10 \, \text{pu} \times \frac{300 \, \text{MVA}}{50 \, \text{MVA}} $$
$$ M_2 = 10 \, \text{pu} \times 6 $$
$$ M_2 = 60 \, \text{pu} $$
Using the reactance conversion formula:
$$ X_2 = X_1 \times \frac{S_{base2}}{S_{base1}} $$
Substitute the given values:
$$ X_2 = 4 \, \text{pu} \times \frac{50 \, \text{MVA}}{300 \, \text{MVA}} $$
$$ X_2 = 4 \, \text{pu} \times \frac{1}{6} $$
$$ X_2 = \frac{4}{6} \, \text{pu} = \frac{2}{3} \, \text{pu} $$
Calculating the decimal value:
$$ X_2 \approx 0.67 \, \text{pu} $$
The per unit values on the new 50 MVA common base are:
Therefore, the correct pair of values is (60, 0.67).
The relation between the old and new per unit impedance values is given by:
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