Let the present ages of Sheo Kumar and Dileep Kumar be $9x$ and $10x$ respectively, according to the given ratio $9 : 10$.
After $11\text{ years}$, their ages will be:
The problem states that after $11\text{ years}$, the ratio of their ages will be $10 : 11$. We can write this as an equation:
$ \frac{9x + 11}{10x + 11} = \frac{10}{11} $Cross-multiply to solve for $x$:
$11(9x + 11) = 10(10x + 11)$
$99x + 121 = 100x + 110$
Rearrange the terms to find $x$:
$121 - 110 = 100x - 99x$
$11 = x$
Now, substitute the value of $x=11$ back into the expressions for their present ages:
Therefore, the present ages are $99\text{ years}$ and $110\text{ years}$.