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Question

The peak output of a tuned amplifier is at 6 MHz and has a quality factor of 60. The bandwidth and 3 dB frequencies shall be

The correct answer is

100 kHz, 6.05 MHz and 5.95 MHz

Tuned Amplifier Analysis: Bandwidth and 3 dB Frequencies

A tuned amplifier is designed to amplify a specific range of frequencies around a central frequency, known as its resonant or peak output frequency. The performance of a tuned amplifier is often characterized by its quality factor (Q) and its bandwidth (BW), which dictates the range of frequencies it effectively amplifies. The 3 dB frequencies (also known as half-power frequencies) mark the points where the amplifier's output power drops to half of its maximum value (or voltage drops to \(1/\sqrt{2}\) of its maximum).

Understanding Key Concepts

  • Peak Output Frequency (\(f_r\)): This is the center frequency where the amplifier provides maximum gain. In this problem, it is given as 6 MHz.
  • Quality Factor (Q): A dimensionless parameter that describes how underdamped an oscillator or resonator is. For a tuned circuit, it relates the resonant frequency to the bandwidth. A higher Q indicates a narrower bandwidth and better selectivity.
  • Bandwidth (BW): The range of frequencies over which the amplifier's gain is within 3 dB of its maximum gain. It is the difference between the upper and lower 3 dB frequencies.
  • 3 dB Frequencies (\(f_1\) and \(f_2\)): These are the lower (\(f_1\)) and upper (\(f_2\)) frequencies at which the amplifier's output power is half of its peak power.

Formulas for Tuned Amplifier Calculations

To calculate the bandwidth and 3 dB frequencies, we use the following standard formulas for tuned amplifiers:

  • Bandwidth (BW): \[ BW = \frac{f_r}{Q} \] where \(f_r\) is the peak output frequency and Q is the quality factor.
  • Lower 3 dB Frequency (\(f_1\)): \[ f_1 = f_r - \frac{BW}{2} \]
  • Upper 3 dB Frequency (\(f_2\)): \[ f_2 = f_r + \frac{BW}{2} \]

Step-by-Step Calculation

Given the following parameters for the tuned amplifier:

  • Peak output frequency, \(f_r\) = 6 MHz
  • Quality factor, Q = 60

1. Bandwidth Calculation

First, we calculate the bandwidth (BW) using the given peak output frequency and quality factor:

\[ BW = \frac{f_r}{Q} = \frac{6 \text{ MHz}}{60} \]

\[ BW = 0.1 \text{ MHz} \]

Since 1 MHz = 1000 kHz, 0.1 MHz can be converted to kHz:

\[ BW = 0.1 \times 1000 \text{ kHz} = 100 \text{ kHz} \]

So, the bandwidth of the tuned amplifier is 100 kHz.

2. 3 dB Frequencies Calculation

Next, we calculate the lower (\(f_1\)) and upper (\(f_2\)) 3 dB frequencies. We first need half of the bandwidth:

\[ \frac{BW}{2} = \frac{100 \text{ kHz}}{2} = 50 \text{ kHz} \]

Convert 50 kHz to MHz for consistency with \(f_r\):

\[ 50 \text{ kHz} = 0.05 \text{ MHz} \]

Now, calculate \(f_1\) and \(f_2\):

  • Lower 3 dB Frequency (\(f_1\)):

    \[ f_1 = f_r - \frac{BW}{2} = 6 \text{ MHz} - 0.05 \text{ MHz} \]

    \[ f_1 = 5.95 \text{ MHz} \]

  • Upper 3 dB Frequency (\(f_2\)):

    \[ f_2 = f_r + \frac{BW}{2} = 6 \text{ MHz} + 0.05 \text{ MHz} \]

    \[ f_2 = 6.05 \text{ MHz} \]

Therefore, the 3 dB frequencies are 5.95 MHz and 6.05 MHz.

Summary of Results

The calculated values are:

  • Bandwidth (BW): 100 kHz
  • Lower 3 dB frequency (\(f_1\)): 5.95 MHz
  • Upper 3 dB frequency (\(f_2\)): 6.05 MHz
Parameter Value
Peak Output Frequency (\(f_r\)) 6 MHz
Quality Factor (Q) 60
Calculated Bandwidth (BW) 100 kHz
Calculated Lower 3 dB Frequency (\(f_1\)) 5.95 MHz
Calculated Upper 3 dB Frequency (\(f_2\)) 6.05 MHz

These results match one of the given options.

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Important Questions from Electrical Resonance

  1. Consider the following statements and choose the correct answer:

    Statement 1: In an RLC series circuit, at half-power frequencies the magnitude of total reactance is equal to resistance.

    Statement 2: In an RLC parallel circuit, at half-power frequencies the magnitude total susceptance is equal to conductance.

  2. If the bandwidth of a band-pass filter increases:

  3. What will be the bandwidth of a series resonant circuit provided it has an inductive reactance of 1000 Ohm, a capacitive reactance of 1000 Ohm and a resistance of 0.1 Ohm? It is also known that the resonant frequency is \(10^6\) rad/sec

  4. A series RLC circuit has a bandwidth of 300 rad/sec at a resonant frequency of 3000 rad/sec when excited by a voltage source of 100 V. The inductance of the coil is 0.1 H. The value of R and the voltage across C are, respectively

  5. The dynamic impedance of a parallel RLC circuit at resonance is

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