The peak output of a tuned amplifier is at 6 MHz and has a quality factor of 60. The bandwidth and 3 dB frequencies shall be
100 kHz, 6.05 MHz and 5.95 MHz
A tuned amplifier is designed to amplify a specific range of frequencies around a central frequency, known as its resonant or peak output frequency. The performance of a tuned amplifier is often characterized by its quality factor (Q) and its bandwidth (BW), which dictates the range of frequencies it effectively amplifies. The 3 dB frequencies (also known as half-power frequencies) mark the points where the amplifier's output power drops to half of its maximum value (or voltage drops to \(1/\sqrt{2}\) of its maximum).
To calculate the bandwidth and 3 dB frequencies, we use the following standard formulas for tuned amplifiers:
Given the following parameters for the tuned amplifier:
First, we calculate the bandwidth (BW) using the given peak output frequency and quality factor:
\[ BW = \frac{f_r}{Q} = \frac{6 \text{ MHz}}{60} \]
\[ BW = 0.1 \text{ MHz} \]
Since 1 MHz = 1000 kHz, 0.1 MHz can be converted to kHz:
\[ BW = 0.1 \times 1000 \text{ kHz} = 100 \text{ kHz} \]
So, the bandwidth of the tuned amplifier is 100 kHz.
Next, we calculate the lower (\(f_1\)) and upper (\(f_2\)) 3 dB frequencies. We first need half of the bandwidth:
\[ \frac{BW}{2} = \frac{100 \text{ kHz}}{2} = 50 \text{ kHz} \]
Convert 50 kHz to MHz for consistency with \(f_r\):
\[ 50 \text{ kHz} = 0.05 \text{ MHz} \]
Now, calculate \(f_1\) and \(f_2\):
\[ f_1 = f_r - \frac{BW}{2} = 6 \text{ MHz} - 0.05 \text{ MHz} \]
\[ f_1 = 5.95 \text{ MHz} \]
\[ f_2 = f_r + \frac{BW}{2} = 6 \text{ MHz} + 0.05 \text{ MHz} \]
\[ f_2 = 6.05 \text{ MHz} \]
Therefore, the 3 dB frequencies are 5.95 MHz and 6.05 MHz.
The calculated values are:
| Parameter | Value |
|---|---|
| Peak Output Frequency (\(f_r\)) | 6 MHz |
| Quality Factor (Q) | 60 |
| Calculated Bandwidth (BW) | 100 kHz |
| Calculated Lower 3 dB Frequency (\(f_1\)) | 5.95 MHz |
| Calculated Upper 3 dB Frequency (\(f_2\)) | 6.05 MHz |
These results match one of the given options.
Consider the following statements and choose the correct answer:
Statement 1: In an RLC series circuit, at half-power frequencies the magnitude of total reactance is equal to resistance.
Statement 2: In an RLC parallel circuit, at half-power frequencies the magnitude total susceptance is equal to conductance.
If the bandwidth of a band-pass filter increases:
What will be the bandwidth of a series resonant circuit provided it has an inductive reactance of 1000 Ohm, a capacitive reactance of 1000 Ohm and a resistance of 0.1 Ohm? It is also known that the resonant frequency is \(10^6\) rad/sec
A series RLC circuit has a bandwidth of 300 rad/sec at a resonant frequency of 3000 rad/sec when excited by a voltage source of 100 V. The inductance of the coil is 0.1 H. The value of R and the voltage across C are, respectively
The dynamic impedance of a parallel RLC circuit at resonance is