All Exams Test series for 1 year @ ₹349 only
Question

The dynamic impedance of a parallel RLC circuit at resonance is

The correct answer is

R

Understanding Parallel RLC Circuit Impedance at Resonance

This solution explains how to determine the dynamic impedance of a parallel RLC circuit specifically when it operates at its resonance frequency. We will derive the impedance value step-by-step.

Parallel RLC Circuit Impedance Formula

The impedance ($Z$) of a parallel RLC circuit, where R is resistance, L is inductance, and C is capacitance, is given by the reciprocal of the total admittance ($Y$). The admittance is the sum of the individual admittances:

$$ Y = \frac{1}{R} + \frac{1}{j\omega L} + j\omega C $$

Where:

  • $R$ is the resistance
  • $L$ is the inductance
  • $C$ is the capacitance
  • $\omega$ is the angular frequency
  • $j$ is the imaginary unit

The impedance is then:

$$ Z = \frac{1}{Y} = \frac{1}{\frac{1}{R} + \frac{1}{j\omega L} + j\omega C} $$

Resonance Condition in Parallel RLC Circuits

Resonance in a parallel RLC circuit occurs when the inductive reactance ($X_L = \omega L$) and the capacitive reactance ($X_C = \frac{1}{\omega C}$) effectively cancel each other out in terms of their contribution to the admittance. Specifically, at resonance, the imaginary part of the admittance becomes zero.

The condition for resonance ($\omega_0$) is when:

$$ \frac{1}{j\omega_0 L} + j\omega_0 C = 0 $$

This simplifies to:

$$ \frac{-j}{\omega_0 L} + j\omega_0 C = 0 $$

$$ j\omega_0 C = \frac{j}{\omega_0 L} $$

$$ \omega_0 C = \frac{1}{\omega_0 L} $$

$$ \omega_0^2 = \frac{1}{LC} $$

So, the resonant angular frequency is $\omega_0 = \frac{1}{\sqrt{LC}}$.

Calculating Dynamic Impedance at Resonance

At the resonant frequency ($\omega_0$), the admittance equation becomes:

$$ Y_{res} = \frac{1}{R} + \frac{1}{j\omega_0 L} + j\omega_0 C $$

As established, at resonance, the term $\frac{1}{j\omega_0 L} + j\omega_0 C$ equals zero.

Therefore, the admittance at resonance simplifies to:

$$ Y_{res} = \frac{1}{R} + 0 = \frac{1}{R} $$

The dynamic impedance ($Z_{res}$) is the reciprocal of the admittance at resonance:

$$ Z_{res} = \frac{1}{Y_{res}} = \frac{1}{\frac{1}{R}} $$

$$ Z_{res} = R $$

Thus, the dynamic impedance of a parallel RLC circuit at resonance is equal to the resistance ($R$). This is the point of maximum impedance for a parallel RLC circuit.

Was this answer helpful?

Important Questions from Electrical Resonance

  1. Consider the following statements and choose the correct answer:

    Statement 1: In an RLC series circuit, at half-power frequencies the magnitude of total reactance is equal to resistance.

    Statement 2: In an RLC parallel circuit, at half-power frequencies the magnitude total susceptance is equal to conductance.

  2. If the bandwidth of a band-pass filter increases:

  3. What will be the bandwidth of a series resonant circuit provided it has an inductive reactance of 1000 Ohm, a capacitive reactance of 1000 Ohm and a resistance of 0.1 Ohm? It is also known that the resonant frequency is \(10^6\) rad/sec

  4. The peak output of a tuned amplifier is at 6 MHz and has a quality factor of 60. The bandwidth and 3 dB frequencies shall be

  5. A series RLC circuit has a bandwidth of 300 rad/sec at a resonant frequency of 3000 rad/sec when excited by a voltage source of 100 V. The inductance of the coil is 0.1 H. The value of R and the voltage across C are, respectively

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App