The following table shows the number of students who appeared in a Common Entrance Test (CET) from six different schools A-F during the years 2020-2022, and the ratio of number of passed (P) to the number of failed (F) students among them. Based on the data in the table, answer the questions: School-wise Appearance of Students in CET during 2020-2022. School 2020 2021 2022 Appeared P ∶ F Appeared P ∶ F Appeared P ∶ F A 1292 11 ∶ 8 1508 7 ∶ 6 1344 3 ∶ 5 B 1694 4 ∶ 7 1690 8 ∶ 5 1904 9 ∶ 8 C 1620 8 ∶ 7 1584 7 ∶ 4 1274 4 ∶ 3 D 1752 7 ∶ 5 1656 11 ∶ 7 1976 7 ∶ 12 E 1740 3 ∶ 2 1452 7 ∶ 4 1430 8 ∶ 5 F 1972 17 ∶ 12 1734 12 ∶ 5 1848 8 ∶ 13
The number of students who passed in the test from School E in the year 2020 is __________ of the number of students who failed in the test from School A in the year 2021.
150%
Count:
In the year 2020, the number of students passing the exam from school E = (3 ÷ 5) × 1740 = 1044
In the year 2021, the number of students failing the exam from school A = (6 ÷ 13) × 1508 = 696
Desired percentage = \(\dfrac{1044}{696} \) × 100 = 150%
∴ In the year 2020, the number of students passing the exam from school E is 150% of the number of students failing the exam from school A in the year 2021.
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