The number of arbitrary constants in a particular solution of a differential equation of 4th order is:
0
A differential equation is an equation that relates a function with its derivatives. The order of a differential equation is the order of the highest derivative appearing in the equation.
The solution to a differential equation describes the function(s) that satisfy the equation. There are generally two types of solutions:
For a differential equation of 4th order:
Once the arbitrary constants in the general solution are replaced by their specific values obtained from the conditions, the resulting solution is the particular solution.
By definition, a particular solution has had its arbitrary constants determined and replaced by fixed numerical values based on given conditions. Therefore, a particular solution does not contain any arbitrary constants.
In the case of a 4th-order differential equation, its general solution has 4 arbitrary constants. However, its particular solution, obtained by applying specific conditions and solving for these constants, will have 0 arbitrary constants remaining.
Therefore, the number of arbitrary constants in a particular solution of a differential equation of 4th order is 0.
| Type of Solution | Contains Arbitrary Constants? | Number of Arbitrary Constants (for order n) | Number of Arbitrary Constants (for 4th order) | How it's Obtained |
|---|---|---|---|---|
| General Solution | Yes | n | 4 | Solving the differential equation |
| Particular Solution | No | 0 | 0 | From the general solution using initial/boundary conditions |
Understanding the difference between general and particular solutions is crucial when working with differential equations. The general solution represents a family of curves that satisfy the equation, while a particular solution represents a single specific curve from that family.
For example, the general solution to the differential equation $\frac{dy}{dx} = 2x$ is $y = x^2 + C$, where $C$ is an arbitrary constant. This is a family of parabolas. If we are given an initial condition, say $y(0) = 5$, we can substitute $x=0$ and $y=5$ into the general solution: $5 = 0^2 + C$, which gives $C=5$. The particular solution is then $y = x^2 + 5$. This particular solution has no arbitrary constants.
The number of arbitrary constants in the general solution directly corresponds to the order of the highest derivative in the differential equation because each integration step introduces one constant of integration.
Degree of the differential equation \( \frac{d^2y}{dx^2} + 3 \left( \frac{dy}{dx} \right)^{\frac{1}{2}} = y^2 + e^x \) is:
General solution of the differential equation \( \frac{2y dx - 3x dy}{y} = 0 \) is (c is an arbitrary constant):
The integrating factor of the differential equation:
\[ x \frac{dy}{dx} - 2y = x^3 \]
is:
If t = e2x and y = loge(t2), then d2y/dx2 is :
The degree of the differential equation
\[\begin{equation*} \left[ 1- \frac{dy}{dx}\right]^{3/2} = k\frac{d^2y}{dx^2} \end{equation*}\]is :
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) Integrating factor of \( xdy - (y + 2x^2)dx = 0 \) | (I) \( \frac{1}{x} \) |
| (B) Integrating factor of \( (2x^2 - 3y)dx = xdy \) | (II) \( x \) |
| (C) Integrating factor of \( (2y + 3x^2)dx + xdy = 0 \) | (III) \( x^2 \) |
| (D) Integrating factor of \( 2xdy + (3x^3 + 2y)dx = 0 \) | (IV) \( x^3 \) |
Choose the correct answer from the options given below:
If \( f(x) = 2 \left( \tan^{-1}(e^x) - \frac{\pi}{4} \right) \), then \( f(x) \) is:
Degree of the differential equation \( \frac{d^2y}{dx^2} + 3 \left( \frac{dy}{dx} \right)^{\frac{1}{2}} = y^2 + e^x \) is: