Degree of the differential equation \( \frac{d^2y}{dx^2} + 3 \left( \frac{dy}{dx} \right)^{\frac{1}{2}} = y^2 + e^x \) is:
2
To determine the degree of a differential equation, we first need to understand what order and degree mean.
Let's find the degree of the given differential equation: \( \frac{d^2y}{dx^2} + 3 \left( \frac{dy}{dx} \right)^{\frac{1}{2}} = y^2 + e^x \)
The given differential equation is:
\( \frac{d^2y}{dx^2} + 3 \left( \frac{dy}{dx} \right)^{\frac{1}{2}} = y^2 + e^x \)
Let's identify the highest order derivative. The derivatives present are \( \frac{dy}{dx} \) (first order) and \( \frac{d^2y}{dx^2} \) (second order). The highest order derivative is \( \frac{d^2y}{dx^2} \), so the order of this differential equation is 2.
Now, we need to find the degree. The equation contains a term with a radical involving a derivative: \( \left( \frac{dy}{dx} \right)^{\frac{1}{2}} \), which is the square root of the first derivative. To find the degree, the equation must be a polynomial in its derivatives. We need to eliminate this radical.
Let's isolate the term with the radical:
\( 3 \left( \frac{dy}{dx} \right)^{\frac{1}{2}} = y^2 + e^x - \frac{d^2y}{dx^2} \)
To remove the square root (power of \( \frac{1}{2} \)), we square both sides of the equation:
\( \left[ 3 \left( \frac{dy}{dx} \right)^{\frac{1}{2}} \right]^2 = \left[ y^2 + e^x - \frac{d^2y}{dx^2} \right]^2 \)
This simplifies to:
\( 9 \left( \frac{dy}{dx} \right) = \left( y^2 + e^x - \frac{d^2y}{dx^2} \right)^2 \)
The differential equation is now in a form where the derivatives appear as powers, without radicals or fractions involving them. We need to find the highest power of the highest order derivative in this equation.
The highest order derivative is \( \frac{d^2y}{dx^2} \). In the equation \( 9 \left( \frac{dy}{dx} \right) = \left( y^2 + e^x - \frac{d^2y}{dx^2} \right)^2 \), the highest order derivative \( \frac{d^2y}{dx^2} \) is inside the term \( \left( y^2 + e^x - \frac{d^2y}{dx^2} \right)^2 \). When this term is expanded, the highest power of \( \frac{d^2y}{dx^2} \) will be \( (\frac{d^2y}{dx^2})^2 \).
Thus, the highest power of the highest order derivative \( \frac{d^2y}{dx^2} \) is 2.
Therefore, the degree of the differential equation is 2.
The degree is 2.
| Characteristic | Value |
|---|---|
| Highest Order Derivative | \( \frac{d^2y}{dx^2} \) |
| Order | 2 |
| Equation after removing radical | \( 9 \frac{dy}{dx} = (y^2 + e^x - \frac{d^2y}{dx^2})^2 \) |
| Highest power of Highest Order Derivative (\( \frac{d^2y}{dx^2} \)) | 2 |
| Degree | 2 |
| Concept | Definition | Example |
|---|---|---|
| Differential Equation | An equation involving derivatives of one or more dependent variables with respect to one or more independent variables. | \( \frac{dy}{dx} = xy \) |
| Order of a Differential Equation | The order of the highest derivative present in the differential equation. | For \( \frac{d^2y}{dx^2} + y = 0 \), Order is 2. |
| Degree of a Differential Equation | The highest power of the highest order derivative after the equation is made free of radicals and fractions in derivatives. | For \( (\frac{dy}{dx})^3 + (\frac{d^2y}{dx^2})^2 = 0 \), Order is 2, Degree is 2. |
| Linear Differential Equation | A differential equation where the dependent variable and its derivatives appear only in the first degree, and there are no products of the dependent variable and/or its derivatives. | \( \frac{dy}{dx} + P(x)y = Q(x) \) |
| Non-linear Differential Equation | A differential equation that is not linear. | \( (\frac{dy}{dx})^2 + y = 0 \) |
Understanding the order and degree is fundamental to classifying and solving differential equations. Here are some related points:
General solution of the differential equation \( \frac{2y dx - 3x dy}{y} = 0 \) is (c is an arbitrary constant):
The number of arbitrary constants in a particular solution of a differential equation of 4th order is:
The integrating factor of the differential equation:
\[ x \frac{dy}{dx} - 2y = x^3 \]
is:
Anubhav spent 14% of his income on electricity bills, 28% on rent and 18% on shopping. If 4/5 of the remaining amount is ₹ 5120, how much did he spend on electricity bills?
Arun's speed of swimming in still water is 5 km/hr. He swims between two points in a river and returns back to the same starting point. He took 20 minutes more to cover the distance upstream than downstream. If the speed of the stream is 2 km/hr, then the distance between the two points is :
If \( f(x) = 2 \left( \tan^{-1}(e^x) - \frac{\pi}{4} \right) \), then \( f(x) \) is:
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) Integrating factor of \( xdy - (y + 2x^2)dx = 0 \) | (I) \( \frac{1}{x} \) |
| (B) Integrating factor of \( (2x^2 - 3y)dx = xdy \) | (II) \( x \) |
| (C) Integrating factor of \( (2y + 3x^2)dx + xdy = 0 \) | (III) \( x^2 \) |
| (D) Integrating factor of \( 2xdy + (3x^3 + 2y)dx = 0 \) | (IV) \( x^3 \) |
Choose the correct answer from the options given below:
If t = e2x and y = loge(t2), then d2y/dx2 is :