All Exams Test series for 1 year @ ₹349 only
Question

The logarithmic mean temperature difference for parallel flow heat exchangers is

The correct answer is \(\rm \frac{\theta_1 - \theta_2}{ \ln (\theta_1 / \theta_2)}\)

Logarithmic Mean Temperature Difference for Parallel Flow Heat Exchangers

Heat exchangers are devices that transfer heat between two or more fluids at different temperatures. Understanding the temperature variation along the length of the heat exchanger is crucial for its design and analysis. The temperature difference between the hot and cold fluids often varies along the heat exchanger's length. To account for this variation in heat transfer calculations, the concept of Logarithmic Mean Temperature Difference (LMTD) is used.

Heat Exchanger Flow Configurations

Heat exchangers can operate in different flow arrangements. Two common types are:

  • Parallel Flow Heat Exchanger: In this configuration, both the hot and cold fluids enter the heat exchanger at the same end and flow in the same direction. As they flow, the hot fluid transfers heat to the cold fluid, causing the temperature of the hot fluid to decrease and the temperature of the cold fluid to increase. The temperature difference between the two fluids is highest at the inlet and decreases along the length of the heat exchanger.
  • Counter Flow Heat Exchanger: In this configuration, the hot and cold fluids enter at opposite ends and flow in opposite directions. This arrangement generally allows for a more effective heat transfer because a more uniform temperature difference can be maintained along the heat exchanger's length.

Logarithmic Mean Temperature Difference (LMTD) Definition

The Logarithmic Mean Temperature Difference (LMTD), denoted as \(\Delta T_{lm}\) or \(\text{LMTD}\), is a method to determine the average temperature difference between the two fluids in a heat exchanger. It is used when the temperature difference varies significantly along the heat transfer surface. The general formula for LMTD is given by:

\[ \text{LMTD} = \frac{\Delta T_1 - \Delta T_2}{\ln\left(\frac{\Delta T_1}{\Delta T_2}\right)} \]

Where:

  • \(\Delta T_1\) represents the temperature difference between the hot and cold fluids at one end of the heat exchanger.
  • \(\Delta T_2\) represents the temperature difference between the hot and cold fluids at the other end of the heat exchanger.

Parallel Flow Heat Exchanger LMTD Calculation

For a parallel flow heat exchanger, the two temperature differences, \(\Delta T_1\) and \(\Delta T_2\), correspond to the temperature differences at the inlet and outlet ends, respectively.

Consider:
\(\theta_1\) = Temperature difference at the inlet of the parallel flow heat exchanger
\(\theta_2\) = Temperature difference at the outlet of the parallel flow heat exchanger

Using these notations, the formula for the Logarithmic Mean Temperature Difference (LMTD) for a parallel flow heat exchanger is:

\[ \text{LMTD}_{\text{parallel flow}} = \frac{\theta_1 - \theta_2}{\ln\left(\frac{\theta_1}{\theta_2}\right)} \]

This formula helps in calculating the total heat transfer rate (Q) in the heat exchanger using the equation:

\[ Q = U A \, \text{LMTD} \]

Where U is the overall heat transfer coefficient and A is the heat transfer area.

Comparing Options for Logarithmic Mean Temperature Difference

Let's examine the given options and compare them with the standard LMTD formula for parallel flow heat exchangers.

Option Formula Comparison with LMTD Standard Formula \(\left(\frac{\theta_1 - \theta_2}{\ln(\theta_1 / \theta_2)}\right)\)
1 \(\rm \frac{\theta_1 - \theta_2}{ \ln (\theta_1 - \theta_2)}\) Incorrect. The denominator should be \(\ln(\theta_1 / \theta_2)\), not \(\ln(\theta_1 - \theta_2)\).
2 \(\rm \frac{\theta_2 - \theta_1}{ \ln (\theta_1 / \theta_2)}\) Incorrect. The numerator should be \(\theta_1 - \theta_2\), not \(\theta_2 - \theta_1\), to maintain consistency with the order in the logarithm. The LMTD must be a positive value.
3 \(\rm \frac{\theta_1 - \theta_2}{ \ln (\theta_1 + \theta_2)}\) Incorrect. The denominator should be \(\ln(\theta_1 / \theta_2)\), not \(\ln(\theta_1 + \theta_2)\).
4 \(\rm \frac{\theta_1 - \theta_2}{ \ln (\theta_1 / \theta_2)}\) Correct. This formula perfectly matches the definition of LMTD for parallel flow heat exchangers where \(\theta_1\) and \(\theta_2\) are the temperature differences at the two ends.

Based on the standard formula for Logarithmic Mean Temperature Difference for parallel flow heat exchangers, option 4 is the correct representation.

Was this answer helpful?

Important Questions from Heat Exchanger Analysis

  1. The fin effectiveness can be enhanced by selecting _____ value of heat transfer co-efficient.

  2. A cold liquid enters a counter flow heat exchanger at 15 deg at a rate of 8 kg/s. A hot stream of the same liquid enters the heat exchanger at 75 deg at 2 kg/s. Assuming the specific heat of the fluid as 4 kJ/kg.°C, determine the maximum heat transfer rate.

  3. For the same inlet and exit temperatures of the hot and cold fluids, the Log mean temperature difference (LMTD) is

  4. In a heat exchanger, the hot liquid enters with a temperature of 180°C and leaves at 160°C. The cooling fluid enters at 30°C and leaves at 110°C. The capacity ratio of the heat exchanger is

  5. NTU effectiveness method for the analysis of heat exchanger is used when:

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App