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Question

The fin effectiveness can be enhanced by selecting _____ value of heat transfer co-efficient.

The correct answer is

low

Understanding Fin Effectiveness and Heat Transfer Coefficient

Fins are extended surfaces used to increase the rate of heat transfer between a surface and a surrounding fluid. The performance of a fin is often evaluated using metrics like fin effectiveness and fin efficiency.

Fin effectiveness ($\epsilon_f$) is defined as the ratio of the heat transfer rate from the finned surface to the heat transfer rate that would occur from the same base area without the fin.

Mathematically, fin effectiveness can be expressed as:

$$\epsilon_f = \frac{Q_{fin}}{Q_{no \, fin}}$$

where:

  • $Q_{fin}$ is the heat transfer rate from the fin.
  • $Q_{no \, fin}$ is the heat transfer rate from the base area if no fin were attached.

$Q_{no \, fin}$ is typically calculated using Newton's law of cooling for the base area ($A_{base}$) with the heat transfer coefficient ($h$):

$$Q_{no \, fin} = h \cdot A_{base} \cdot (T_{base} - T_{\infty})$$

where $T_{base}$ is the base temperature and $T_{\infty}$ is the fluid temperature.

For the fin to be effective, meaning it actually enhances heat transfer, the fin effectiveness ($\epsilon_f$) should be greater than 1. If $\epsilon_f = 1$, the fin transfers the same amount of heat as the base area alone. If $\epsilon_f < 1$, adding the fin actually reduces heat transfer, which is undesirable.

Relation between Fin Effectiveness and Heat Transfer Coefficient

Let's consider how the heat transfer coefficient ($h$) influences fin effectiveness ($\epsilon_f$). The heat transfer from the fin to the fluid is primarily through convection, which is governed by the heat transfer coefficient ($h$).

A general expression for the heat transfer rate from a fin involves terms related to the fin geometry, thermal conductivity of the fin material ($k$), and the heat transfer coefficient ($h$). A simplified model for fin effectiveness for a long fin is often given as:

$$\epsilon_f = \sqrt{\frac{k P}{h A_c}}$$

where:

  • $k$ is the thermal conductivity of the fin material.
  • $P$ is the perimeter of the fin.
  • $A_c$ is the cross-sectional area of the fin.

From this expression, we can see that fin effectiveness ($\epsilon_f$) is inversely proportional to the square root of the heat transfer coefficient ($h$).

$$\epsilon_f \propto \frac{1}{\sqrt{h}}$$

This relationship tells us that:

  • As the heat transfer coefficient ($h$) increases, the fin effectiveness ($\epsilon_f$) decreases.
  • As the heat transfer coefficient ($h$) decreases, the fin effectiveness ($\epsilon_f$) increases.

Therefore, fins are most effective (provide the greatest enhancement in heat transfer) when the convection heat transfer coefficient is low. Situations with low heat transfer coefficients include natural convection or gas flow. In cases with high heat transfer coefficients, such as boiling or condensation, fins are typically less effective, and other methods might be more suitable for heat transfer enhancement.

Analyzing the Options

Based on the inverse relationship between fin effectiveness and the heat transfer coefficient, to enhance fin effectiveness, we need to select a value of heat transfer coefficient that makes the effectiveness higher.

  • Low heat transfer coefficient: A low $h$ leads to higher $\epsilon_f$. This enhances the fin effectiveness.
  • Zero heat transfer coefficient: A zero $h$ implies no convection, which isn't a practical scenario for heat transfer enhancement using fins in a fluid.
  • High heat transfer coefficient: A high $h$ leads to lower $\epsilon_f$. This reduces the enhancement provided by the fin.
  • Positive heat transfer coefficient: The heat transfer coefficient is always a positive value in practical heat transfer scenarios. This option doesn't specify whether it's high or low.

Thus, fin effectiveness is enhanced by selecting a low value of heat transfer coefficient.

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Important Questions from Heat Exchanger Analysis

  1. The logarithmic mean temperature difference for parallel flow heat exchangers is

  2. A cold liquid enters a counter flow heat exchanger at 15 deg at a rate of 8 kg/s. A hot stream of the same liquid enters the heat exchanger at 75 deg at 2 kg/s. Assuming the specific heat of the fluid as 4 kJ/kg.°C, determine the maximum heat transfer rate.

  3. For the same inlet and exit temperatures of the hot and cold fluids, the Log mean temperature difference (LMTD) is

  4. In a heat exchanger, the hot liquid enters with a temperature of 180°C and leaves at 160°C. The cooling fluid enters at 30°C and leaves at 110°C. The capacity ratio of the heat exchanger is

  5. NTU effectiveness method for the analysis of heat exchanger is used when:

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