The least number of square tiles required to pave the ceiling of a room 15 m 17 cm long and 9 m 2 cm broad is
This question asks for the minimum number of identical square tiles needed to perfectly cover a rectangular ceiling. The ceiling dimensions are given as length 15 m 17 cm and breadth 9 m 2 cm. To minimize the number of tiles, we must use the largest possible square tile size. The side length of this largest square tile is determined by the Greatest Common Divisor (GCD) of the ceiling's length and breadth.
First, we need to express both the length and the breadth in the same unit. Let's convert everything to centimeters (cm) as it avoids decimals.
So, the ceiling measures 1517 cm in length and 902 cm in breadth.
The side length of the largest square tile that can perfectly pave the ceiling must be a divisor of both the length (1517 cm) and the breadth (902 cm). The largest such side length corresponds to the Greatest Common Divisor (GCD) of 1517 and 902.
We will use the Euclidean Algorithm to find the GCD:
$1517 = 1 \times 902 + 615$
$902 = 1 \times 615 + 287$
$615 = 2 \times 287 + 41$
$287 = 7 \times 41 + 0$
The last non-zero remainder is 41. Therefore, the GCD(1517, 902) = 41.
This means the side length of the largest possible square tile we can use is 41 cm.
With the ceiling dimensions (1517 cm $\times$ 902 cm) and the tile side length (41 cm), we can now find the number of tiles required. The total number of tiles is the area of the ceiling divided by the area of a single tile.
Number of Tiles = $ \frac{\text{Area of Ceiling}}{\text{Area of one Tile}} $
Number of Tiles = $ \frac{1517 \text{ cm} \times 902 \text{ cm}}{41 \text{ cm} \times 41 \text{ cm}} $
This calculation can be simplified by dividing the dimensions by the tile side length first:
Number of Tiles = $ \left( \frac{1517}{41} \right) \times \left( \frac{902}{41} \right) $
Performing the divisions:
Now, multiply these two numbers to get the total number of tiles:
Total Number of Tiles = $ 37 \times 22 $
Total Number of Tiles = $ 814 $
The calculation shows that 814 square tiles, each with a side length of 41 cm, are required to pave the ceiling.
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