The Largest possible sphere is carved our of a cube of side 6 cm. What is the volume of the sphere?
792/7 cm3
Let's break down this geometry problem step by step. We are given a cube with a side length of 6 cm, and we need to find the volume of the largest possible sphere that can be carved out of it.
When the largest possible sphere is carved from a cube, the key relationship is that the diameter of the sphere must be equal to the side length of the cube. Any larger sphere would not fit entirely within the cube's boundaries.
So, the radius of the sphere is 3 cm.
The formula for the volume of a sphere is given by:
\(V = \frac{4}{3}\pi r^3\)
where \(V\) is the volume and \(r\) is the radius. We can use the approximation \(\pi \approx \frac{22}{7}\) as the options are given in fractions involving 7.
Substitute the radius \(r = 3\) cm into the formula:
\(V = \frac{4}{3} \times \frac{22}{7} \times (3 \text{ cm})^3\)
Calculate the cube of the radius:
\((3 \text{ cm})^3 = 3 \times 3 \times 3 \text{ cm}^3 = 27 \text{ cm}^3\)
Now, substitute this back into the volume formula:
\(V = \frac{4}{3} \times \frac{22}{7} \times 27 \text{ cm}^3\)
We can simplify the calculation by cancelling out the 3 in the denominator with the 27:
\(V = 4 \times \frac{22}{7} \times \frac{27}{3} \text{ cm}^3\)
\(V = 4 \times \frac{22}{7} \times 9 \text{ cm}^3\)
Now, multiply the numbers together:
\(V = (4 \times 22 \times 9) \div 7 \text{ cm}^3\)
\(V = (88 \times 9) \div 7 \text{ cm}^3\)
\(V = 792 \div 7 \text{ cm}^3\)
So, the volume of the largest sphere that can be carved from the cube is \(\frac{792}{7}\) cm3.
| Dimension | Value |
|---|---|
| Cube Side Length | 6 cm |
| Sphere Diameter | 6 cm |
| Sphere Radius | 3 cm |
| Sphere Volume Formula | \(\frac{4}{3}\pi r^3\) |
| Calculated Volume (\(\pi \approx 22/7\)) | \(\frac{792}{7}\) cm3 |
The calculated volume is \(\frac{792}{7}\) cm3, which matches one of the given options.
| Shape | Key Dimension | Volume Formula | Relation (Carving Largest Sphere from Cube) |
|---|---|---|---|
| Cube | Side Length (\(s\)) | \(s^3\) | \(s = \) Sphere Diameter |
| Sphere | Radius (\(r\)) | \(\frac{4}{3}\pi r^3\) | Diameter (\(2r\)) = Cube Side (\(s\)) |
When one shape is carved out of another, the dimensions of the carved shape are limited by the dimensions of the original shape. For carving the largest possible shape, the critical dimensions must match at their limits.
These relationships are crucial for solving problems involving volumes and dimensions of shapes carved from other shapes.
If a cubical container of length, breadth and height each of 10 cm can contain exactly 1 litre of water, then a spherical container of radius 10.5 cm can contain