The given sequence is: 1, x, x, x, y, y, 9, 16, 18. It is in increasing order.
The number of elements in the sequence is 9.
We are given that Mean = Median = 2 * Mode.
We need to find the value of y.
Since the sequence is increasing, we have 1 < x < y < 9.
We are given that Median = 2 * Mode.
Substituting the values:
$y = 2 * x$ (Equation 1)
The sum of the numbers is: $1 + x + x + x + y + y + 9 + 16 + 18 = 3x + 2y + 44$.
The mean is the sum divided by the count (9):
Mean = $ \frac{3x + 2y + 44}{9} $
We are given that Mean = Median.
Substituting the expressions:
$ \frac{3x + 2y + 44}{9} = y $
Multiply both sides by 9:
$ 3x + 2y + 44 = 9y $
Rearrange the terms:
$ 3x + 44 = 7y $ (Equation 2)
Substitute Equation 1 ($y = 2x$) into Equation 2:
$ 3x + 44 = 7(2x) $
$ 3x + 44 = 14x $
Subtract $3x$ from both sides:
$ 44 = 11x $
Solve for $x$:
$ x = \frac{44}{11} $
$ x = 4 $
Now substitute the value of $x$ back into Equation 1 ($y = 2x$) to find $y$:
$ y = 2 \times 4 $
$ y = 8 $
With x=4 and y=8, the sequence is 1, 4, 4, 4, 8, 8, 9, 16, 18.
Therefore, the value of y is 8.

The above frequency chart shows the frequency distribution of marks obtained by a set of students in an exam. From the data presented above, which one of the following is CORRECT?