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Question

The flow rates of hot and cold water streams running through a parallel flow heat exchanger are 0.2 Kg/sec and 0.5 Kg/sec respectively. The inlet temperatures on hot and cold sides are 75°C and 20°C respectively. The exit temperature of hot water is 45°C. Calculate LMTD of heat exchanger.

The correct answer is

29.12°C

Energy balance gives \(T_{c,o}=20+\frac{0.2}{0.5}(75-45)=32^\circ\mathrm C\). For parallel flow, endpoint temperature differences are \(\Delta T_1=75-20=55^\circ\mathrm C\) and \(\Delta T_2=45-32=13^\circ\mathrm C\). Thus \(\Delta T_{lm}=\frac{55-13}{\ln(55/13)}\approx29.12^\circ\mathrm C\).

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Important Questions from Heat Exchanger Analysis

  1. The logarithmic mean temperature difference for parallel flow heat exchangers is

  2. The fin effectiveness can be enhanced by selecting _____ value of heat transfer co-efficient.

  3. A cold liquid enters a counter flow heat exchanger at 15 deg at a rate of 8 kg/s. A hot stream of the same liquid enters the heat exchanger at 75 deg at 2 kg/s. Assuming the specific heat of the fluid as 4 kJ/kg.°C, determine the maximum heat transfer rate.

  4. For the same inlet and exit temperatures of the hot and cold fluids, the Log mean temperature difference (LMTD) is

  5. In a heat exchanger, the hot liquid enters with a temperature of 180°C and leaves at 160°C. The cooling fluid enters at 30°C and leaves at 110°C. The capacity ratio of the heat exchanger is

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