$s^3$ 3 3 $s^2$ 4 4
The problem asks to infer the location of system poles from the first two rows of a Routh table for a third-order characteristic equation. A standard third-order characteristic equation is given by $a_3s^3 + a_2s^2 + a_1s + a_0 = 0$. Based on the provided information, interpreted as coefficients related to the initial Routh table rows ($s^3$ coefficient assumed to be 1), we infer $a_3 = 1$, $a_2 = 33$, and $a_1 = 44$. The characteristic equation becomes $s^3 + 33s^2 + 44s + a_0 = 0$.
The first two rows of the Routh table are constructed using the coefficients of the characteristic equation:
| Row | Coeff 1 | Coeff 2 |
| $s^3$ | 1 | 44 |
| $s^2$ | 33 | $a_0$ |
The elements of the $s^1$ row ($b_1, b_2$) are calculated using the Routh recurrence relation. The first element ($b_1$) is:
$b_1 = \frac{(33 \times 44) - (1 \times a_0)}{33} = 44 - \frac{a_0}{33}$
The second element ($b_2$) is calculated as 0.
Poles are located on the imaginary axis of the s-plane if a complete row of zeros appears in the Routh table. For this third-order system, this occurs when the first element of the $s^1$ row, $b_1$, is zero.
Setting $b_1 = 0$ allows us to find the specific value of $a_0$ that leads to poles on the imaginary axis:
$44 - \frac{a_0}{33} = 0$
$\frac{a_0}{33} = 44$
$a_0 = 44 \times 33 = 1452$
When a row of zeros is encountered, the auxiliary polynomial is formed using the coefficients from the row immediately preceding it (the $s^2$ row). The auxiliary polynomial $A(s)$ is:
$A(s) = 33s^2 + a_0$
Substituting $a_0 = 1452$:
$33s^2 + 1452 = 0$
Solving for $s$ gives the locations of the poles:
$33s^2 = -1452$
$s^2 = -\frac{1452}{33} = -44$
$s = \pm \sqrt{-44} = \pm j\sqrt{44} = \pm j2\sqrt{11}$
These roots indicate a pair of complex conjugate poles situated exactly on the imaginary axis of the s-plane.
Match List I with List II:
List I (Coefficients of s 2+ a 1s + a 2= 0) | List II (Nature of Roots) | ||
| (A) | a \(_1^2\) > 4a 2 | (I) | Negative real and equal |
| (B) | a \(_1^2\) = 4a 2 | (II) | Conjugate Imaginary |
| (C) | a \(_1^2\) < 4a 2 | (III) | Negative Real and Unequal |
| (D) | a 1= 0 a 2≠ 0 | (IV) | Conjugate Complex (Real part negative) |
Choose the correct answer from the options given below:
A closed-loop control system has a characteristic equation given by s 3 + 2.4s 2 + 1.8s + 0.5 = 0. Find out the value of a, b, c, and d using the Routh Hurwitz criterion.
s 3 | 1 | 1.8 |
s 2 | 2.4 | 0.5 |
s 1 | a | c |
s 0 | b | d |
Determine the stability of system:
S 3+ S 2+ S + 4
Which of the following is NOT the advantage of Routh-Hurwitz criterion of control systems?
The characteristic equation of given system is 6s + K = 0. Determined the range of K for which the system to be stable.