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Question

The first two rows of Routh's table of a third-order characteristic equation are
$s^3$33
$s^2$44
It can be inferred that the system has

The correct answer is
a pair of complex conjugate poles on the imaginary axis of the s-plane

Routh Table Analysis for Pole Location

The problem asks to infer the location of system poles from the first two rows of a Routh table for a third-order characteristic equation. A standard third-order characteristic equation is given by $a_3s^3 + a_2s^2 + a_1s + a_0 = 0$. Based on the provided information, interpreted as coefficients related to the initial Routh table rows ($s^3$ coefficient assumed to be 1), we infer $a_3 = 1$, $a_2 = 33$, and $a_1 = 44$. The characteristic equation becomes $s^3 + 33s^2 + 44s + a_0 = 0$.

Routh Table Construction

The first two rows of the Routh table are constructed using the coefficients of the characteristic equation:

Row Coeff 1 Coeff 2
$s^3$ 1 44
$s^2$ 33 $a_0$

Calculating the $s^1$ Row

The elements of the $s^1$ row ($b_1, b_2$) are calculated using the Routh recurrence relation. The first element ($b_1$) is:

$b_1 = \frac{(33 \times 44) - (1 \times a_0)}{33} = 44 - \frac{a_0}{33}$

The second element ($b_2$) is calculated as 0.

Condition for Imaginary Axis Poles

Poles are located on the imaginary axis of the s-plane if a complete row of zeros appears in the Routh table. For this third-order system, this occurs when the first element of the $s^1$ row, $b_1$, is zero.

Determining the Value of $a_0$

Setting $b_1 = 0$ allows us to find the specific value of $a_0$ that leads to poles on the imaginary axis:

$44 - \frac{a_0}{33} = 0$

$\frac{a_0}{33} = 44$

$a_0 = 44 \times 33 = 1452$

Auxiliary Polynomial and Pole Location

When a row of zeros is encountered, the auxiliary polynomial is formed using the coefficients from the row immediately preceding it (the $s^2$ row). The auxiliary polynomial $A(s)$ is:

$A(s) = 33s^2 + a_0$

Substituting $a_0 = 1452$:

$33s^2 + 1452 = 0$

Solving for $s$ gives the locations of the poles:

$33s^2 = -1452$

$s^2 = -\frac{1452}{33} = -44$

$s = \pm \sqrt{-44} = \pm j\sqrt{44} = \pm j2\sqrt{11}$

These roots indicate a pair of complex conjugate poles situated exactly on the imaginary axis of the s-plane.

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Important Questions from Routh-Hurwitz Stability Criteria

  1. Match List I with List II:

    List I

    (Coefficients of s 2+ a 1s + a 2= 0)

    List II

    (Nature of Roots)

    (A)a \(_1^2\) > 4a 2(I)Negative real and equal
    (B)a \(_1^2\) = 4a 2(II)Conjugate Imaginary
    (C)a \(_1^2\) < 4a 2(III)Negative Real and Unequal
    (D)

    a 1= 0

    a 2≠ 0

    (IV)Conjugate Complex (Real part negative)

    Choose the correct answer from the options given below:

  2. A closed-loop control system has a characteristic equation given by s 3 + 2.4s + 1.8s + 0.5 = 0. Find out the value of a, b, c, and d using the Routh Hurwitz criterion.

    s 3

    1

    1.8

    s 2

    2.4

    0.5

    s 1

    a

    c

    s 0

    b

    d

  3. Determine the stability of system:

    S 3+ S 2+ S + 4

  4. Which of the following is NOT the advantage of Routh-Hurwitz criterion of control systems?

  5. The characteristic equation of given system is 6s + K = 0. Determined the range of K for which the system to be stable.

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