Determine the stability of system: S 3+ S 2+ S + 4
Unstable
To determine the stability of a given system, we utilize the Routh-Hurwitz stability criterion. This powerful mathematical tool helps us identify if any roots of the system's characteristic equation lie in the right half of the S-plane, which would indicate an unstable system. The presence of roots with positive real parts signifies that the system's output will grow unbounded over time, leading to instability.
In the field of control systems, stability is a fundamental property. A stable system is one that returns to or stays near its equilibrium state after being subjected to a disturbance. Conversely, an unstable system will diverge from its equilibrium state following a disturbance, leading to an uncontrolled output. The stability of a linear time-invariant (LTI) system is directly determined by the locations of the roots of its characteristic equation. Specifically, if even one root of the characteristic equation has a positive real part (i.e., lies in the right half of the S-plane), the system is considered unstable.
The Routh-Hurwitz criterion offers a systematic method to ascertain the number of roots of a polynomial that possess positive real parts without the need to explicitly calculate these roots. This is achieved through the construction and analysis of a specific tabular arrangement known as the Routh array.
The given characteristic equation of the system is:
$$S^3 + S^2 + S + 4 = 0$$This is a third-order polynomial. When compared to the general form of a polynomial $a_n S^n + a_{n-1} S^{n-1} + \dots + a_1 S + a_0 = 0$, the coefficients for our equation are:
The Routh array is constructed using the coefficients of the characteristic equation. The first two rows of the array are populated directly from these coefficients, alternating between terms.
| Row | Coefficient 1 | Coefficient 2 |
|---|---|---|
| $S^3$ | $a_3 = 1$ | $a_1 = 1$ |
| $S^2$ | $a_2 = 1$ | $a_0 = 4$ |
Next, we compute the elements for the subsequent rows ($S^1$ and $S^0$) using specific determinant-like formulas based on the elements in the two rows directly above them.
For the $S^1$ row, the first element ($b_1$) is calculated as:
$$b_1 = \frac{(a_2 \times a_1) - (a_3 \times a_0)}{a_2}$$ $$b_1 = \frac{(1 \times 1) - (1 \times 4)}{1} = \frac{1 - 4}{1} = \frac{-3}{1} = -3$$The second element ($b_2$) for the $S^1$ row would involve coefficients from further columns, but since there are no more, $b_2 = 0$.
For the $S^0$ row, the first element ($c_1$) is calculated using the elements from the $S^2$ and $S^1$ rows:
$$c_1 = \frac{(b_1 \times a_0) - (a_2 \times b_2)}{b_1}$$ $$c_1 = \frac{(-3 \times 4) - (1 \times 0)}{-3} = \frac{-12 - 0}{-3} = \frac{-12}{-3} = 4$$Now, we can present the complete Routh array:
| Row | Coefficient 1 | Coefficient 2 |
|---|---|---|
| $S^3$ | $1$ | $1$ |
| $S^2$ | $1$ | $4$ |
| $S^1$ | $-3$ | $0$ |
| $S^0$ | $4$ | $0$ |
The stability of the system is solely determined by examining the signs of the elements in the first column of the Routh array. The elements in the first column are:
$$1, 1, -3, 4$$Let's trace the sign changes as we move from top to bottom:
In total, there are two sign changes observed in the first column of the Routh array.
Based on the Routh-Hurwitz criterion, the interpretation of the sign changes in the first column is straightforward:
Since our analysis revealed two sign changes in the first column of the Routh array, it signifies that two roots of the characteristic equation $S^3 + S^2 + S + 4 = 0$ lie in the right half of the S-plane. The presence of any root in the right half of the S-plane causes the system to be unstable, as it leads to an unbounded response over time.
Therefore, the system described by the characteristic equation $S^3 + S^2 + S + 4 = 0$ is definitively unstable.
Match List I with List II:
List I (Coefficients of s 2+ a 1s + a 2= 0) | List II (Nature of Roots) | ||
| (A) | a \(_1^2\) > 4a 2 | (I) | Negative real and equal |
| (B) | a \(_1^2\) = 4a 2 | (II) | Conjugate Imaginary |
| (C) | a \(_1^2\) < 4a 2 | (III) | Negative Real and Unequal |
| (D) | a 1= 0 a 2≠ 0 | (IV) | Conjugate Complex (Real part negative) |
Choose the correct answer from the options given below:
A closed-loop control system has a characteristic equation given by s 3 + 2.4s 2 + 1.8s + 0.5 = 0. Find out the value of a, b, c, and d using the Routh Hurwitz criterion.
s 3 | 1 | 1.8 |
s 2 | 2.4 | 0.5 |
s 1 | a | c |
s 0 | b | d |
Which of the following is NOT the advantage of Routh-Hurwitz criterion of control systems?
The characteristic equation of given system is 6s + K = 0. Determined the range of K for which the system to be stable.
The number of roots of s 3+ 5s 2+ 7s + 3 = 0 in the left half of the s-plane is