A closed-loop control system has a characteristic equation given by s 3 + 2.4s 2 + 1.8s + 0.5 = 0. Find out the value of a, b, c, and d using the Routh Hurwitz criterion. s 3 1 1.8 s 2 2.4 0.5 s 1 a c s 0 b d
a = 1.59, b = 0.5, c = 0, d = 0
The Routh-Hurwitz criterion is a mathematical test used to determine the stability of a linear time-invariant (LTI) control system by examining the roots of its characteristic equation. A system is considered stable if all the roots of its characteristic equation have negative real parts. The Routh-Hurwitz criterion allows us to determine this without explicitly calculating the roots.
The given characteristic equation for the closed-loop control system is:
$$\text{s}^3 + 2.4\text{s}^2 + 1.8\text{s} + 0.5 = 0$$
To apply the Routh-Hurwitz criterion, we first construct the Routh array. The coefficients of the characteristic equation are arranged in a specific pattern to form the initial two rows of the array.
The given incomplete Routh array is:
| s3 | 1 | 1.8 |
|---|---|---|
| s2 | 2.4 | 0.5 |
| s1 | a | c |
| s0 | b | d |
We need to calculate the values for 'a' and 'c' for the s1 row. These are calculated using the elements from the two rows above it (s3 and s2 rows).
The formula for 'a' is:
$$a = \frac{(2.4 \times 1.8) - (1 \times 0.5)}{2.4}$$
Let's perform the calculation:
$$a = \frac{4.32 - 0.5}{2.4}$$
$$a = \frac{3.82}{2.4}$$
$$a \approx 1.59166$$
Rounding to two decimal places, we get:
$$a \approx 1.59$$
The formula for 'c' is derived similarly, using the next column of coefficients (which are effectively zeros beyond the given terms):
$$c = \frac{(2.4 \times 0) - (1 \times 0)}{2.4}$$
$$c = \frac{0 - 0}{2.4}$$
$$c = 0$$
Next, we calculate the values for 'b' and 'd' for the s0 row. These are calculated using the elements from the s2 and s1 rows.
The formula for 'b' is:
$$b = \frac{(a \times 0.5) - (2.4 \times c)}{a}$$
Substitute the calculated values of 'a' and 'c':
$$b = \frac{(1.59166 \times 0.5) - (2.4 \times 0)}{1.59166}$$
$$b = \frac{0.79583 - 0}{1.59166}$$
$$b = \frac{0.79583}{1.59166}$$
$$b = 0.5$$
The formula for 'd' is:
$$d = \frac{(a \times 0) - (2.4 \times 0)}{a}$$
$$d = \frac{0 - 0}{a}$$
$$d = 0$$
After calculating all the unknown elements, the complete Routh array is:
| s3 | 1 | 1.8 |
|---|---|---|
| s2 | 2.4 | 0.5 |
| s1 | 1.59 | 0 |
| s0 | 0.5 | 0 |
Based on our calculations using the Routh-Hurwitz criterion, the values for a, b, c, and d are:
For a system to be stable, all the elements in the first column of the Routh array must have the same sign (and generally, all positive for common engineering systems). In this completed array, the first column elements are 1, 2.4, 1.59, and 0.5, all of which are positive, indicating a stable system.
The disadvantage of the Routh's criteria are
Which of the following is NOT the advantage of Routh-Hurwitz criterion of control systems?
Which of the following is the correct comment on stability based on unknown k for the feedback system with characteristic s4 + 2ks3 + s2 + 5s + 5 = 0?
Match the inferences X, Y, and Z, about a system, to the corresponding properties of the elements of first column in Routh’s Table of the system characteristic equation.
X: The system is stable …
Y: The system is unstable …
Z: The test breaks down …
P: … when all elements are positive
Q: … when any one element is zero
R: … when there is a change in sign of coefficients
A system with the open loop transfer function
\(G\left( s \right) = \frac{K}{{s\left( {s + 2} \right)\left( {{s^2} + 2s + 2} \right)}}\)
is connected in a negative feedback configuration with a feedback gain of unity. For the closed loop system to be marginally stable, the value of K is ______