The open loop transfer function of a unity gain negative feedback system is given by \(\rm G(s) = \frac{k}{s^2 + 4s - 5}\) The range of ЁЭСШ for which the system is stable, is
k > 5
The question asks for the range of the parameter k that ensures stability for a unity gain negative feedback control system. The open-loop transfer function (OLTF) is given as:
$$ \rm G(s) = \frac{k}{s^2 + 4s - 5} $$
For a unity gain negative feedback system, the closed-loop transfer function (CLTF) is given by:
$$ \rm CLTF(s) = \frac{G(s)}{1 + G(s)} $$
The stability of the system is determined by the roots of the characteristic equation, which is the denominator of the CLTF set to zero:
$$ 1 + G(s) = 0 $$
Substituting the given G(s):
$$ 1 + \frac{k}{s^2 + 4s - 5} = 0 $$
To find the characteristic equation, we clear the denominator:
$$ s^2 + 4s - 5 + k = 0 $$
Rearranging the terms to match the standard polynomial form:
$$ s^2 + 4s + (k-5) = 0 $$
The Routh-Hurwitz criterion is a method used to determine the stability of a linear time-invariant (LTI) system by examining the coefficients of its characteristic equation without explicitly calculating the roots. For a polynomial to have all its roots in the left-half of the s-plane (which is required for stability), all coefficients must be present and positive, and all elements in the first column of the Routh array must have the same sign (typically positive).
The characteristic polynomial is: $$ P(s) = 1 \cdot s^2 + 4 \cdot s^1 + (k-5) \cdot s^0 $$
We construct the Routh array using the coefficients of the characteristic polynomial:
| \( s^2 \) | 1 | \( k-5 \) |
| \( s^1 \) | 4 | 0 |
| \( s^0 \) | \( \frac{4(k-5) - 1(0)}{4} \) | 0 |
Simplifying the term for the \( s^0 \) row:
$$ \text{Term for } s^0 = \frac{4(k-5)}{4} = k-5 $$
The Routh array is:
| \( s^2 \) | 1 | \( k-5 \) |
| \( s^1 \) | 4 | 0 |
| \( s^0 \) | \( k-5 \) | 0 |
For the system to be stable, all the elements in the first column of the Routh array must be positive.
Therefore, we require:
$$ k-5 > 0 $$
Solving for k:
$$ k > 5 $$
If \( k = 5 \), the \( s^0 \) row becomes zero, indicating the presence of roots on the imaginary axis (marginal stability). For strict stability, k must be greater than 5.
Thus, the range of k for which the system is stable is k > 5.
A closed-loop control system has a characteristic equation given by s 3 + 2.4s 2 + 1.8s + 0.5 = 0. Find out the value of a, b, c, and d using the Routh Hurwitz criterion.
s 3 | 1 | 1.8 |
s 2 | 2.4 | 0.5 |
s 1 | a | c |
s 0 | b | d |
The disadvantage of the Routh's criteria are
Which of the following is NOT the advantage of Routh-Hurwitz criterion of control systems?
The characteristic polynomial of a linear system is given as s4 + 3s3 + 5s2 + 6s + K + 10=0. What should be the condition on K so that the system is stable ?
Which of the following is the correct comment on stability based on unknown k for the feedback system with characteristic s4 + 2ks3 + s2 + 5s + 5 = 0?