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Question

The first two rows in the Routh table for the characteristic equation of a certain closed-loop control system are given as

The range of $K$ for which the system is stable is

The correct answer is
0.5 < K < $\infty$

To determine the range of \( K \) for which the system is stable, we need to construct the Routh array using the given table and apply the Routh-Hurwitz stability criterion.

The first two rows of the Routh array are given as:

The Routh array is constructed as follows:

   
\( s^3 \)1\( 2K + 3 \)
\( s^2 \)2K4
\( s^1 \)\(\frac{(2K)(2K+3) - 4 \cdot 1}{2K}\)0
\( s^0 \)4 

We need the first column elements of the Routh array to be positive for stability:

  1. For \( s^3 \), the coefficient is 1, which is already positive.
  2. For \( s^2 \), the coefficient is \( 2K \). \(2K > 0\) implies \( K > 0 \).
  3. Now, calculate the coefficient for \( s^1 \):

The coefficient for \( s^1 \) is given by:

\[\frac{(2K)(2K+3) - 4 \cdot 1}{2K} = \frac{4K^2 + 6K - 4}{2K} = 2K + 3 - \frac{2}{K}\]

For stability, \( 2K + 3 - \frac{2}{K} > 0 \).

  1. Simplifying, we get:
\[2K^2 + 3K - 2 > 0\]
  1. Solving the quadratic inequality \( 2K^2 + 3K - 2 = 0 \) using the quadratic formula:
\[K = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{-3 \pm \sqrt{9 + 16}}{4} = \frac{-3 \pm 5}{4}\]

Thus, \( K = \frac{1}{2} \) or \( K = -2 \).

The solution to the inequality involves testing intervals determined by roots \( K = -2 \) and \( K = \frac{1}{2} \). The expression \( 2K^2 + 3K - 2 > 0 \) is satisfied for:

\[K > \frac{1}{2} \, \text{or} \, K < -2\]

Since \( K > 0 \) is also a requirement for stability, the valid range for stable \( K \) is:

0.5 < K < \(\infty\)

Therefore, the correct answer is 0.5 < K < \(\infty\).

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Important Questions from Routh-Hurwitz Stability Criteria

  1. Match List I with List II:

    List I

    (Coefficients of s 2+ a 1s + a 2= 0)

    List II

    (Nature of Roots)

    (A)a \(_1^2\) > 4a 2(I)Negative real and equal
    (B)a \(_1^2\) = 4a 2(II)Conjugate Imaginary
    (C)a \(_1^2\) < 4a 2(III)Negative Real and Unequal
    (D)

    a 1= 0

    a 2≠ 0

    (IV)Conjugate Complex (Real part negative)

    Choose the correct answer from the options given below:

  2. A closed-loop control system has a characteristic equation given by s 3 + 2.4s + 1.8s + 0.5 = 0. Find out the value of a, b, c, and d using the Routh Hurwitz criterion.

    s 3

    1

    1.8

    s 2

    2.4

    0.5

    s 1

    a

    c

    s 0

    b

    d

  3. Determine the stability of system:

    S 3+ S 2+ S + 4

  4. Which of the following is NOT the advantage of Routh-Hurwitz criterion of control systems?

  5. The characteristic equation of given system is 6s + K = 0. Determined the range of K for which the system to be stable.

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