Calculating Average Speed: Flight X to Y and Back
This problem requires calculating the average speed of a flight based on distance and time, specifically focusing only on the time spent in the air.
Flight Durations Analysis
- Trip X to Y:
- Departure Time (X): 8 AM local time
- Arrival Time (Y): 10 AM local time
- Air Time (X to Y): 10 AM - 8 AM = 2 hours
- Return Trip Y to X:
- Arrival Time (Y): 10 AM local time
- Halt Duration (Y): 4 hours
- Departure Time (Y): 10 AM + 4 hours = 2 PM local time
- Arrival Time (X): 4 PM local time
- Air Time (Y to X): 4 PM - 2 PM = 2 hours
- Total Air Time: 2 hours (X to Y) + 2 hours (Y to X) = 4 hours
Total Distance Calculation
The distance between X and Y is given as 1000 km.
- Distance (X to Y) = 1000 km
- Distance (Y to X) = 1000 km
- Total Distance Travelled: 1000 km + 1000 km = 2000 km
Average Speed Calculation
The formula for average speed is:
$ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time in Air}} $
Substituting the calculated values:
$ \text{Average Speed} = \frac{2000 \text{ km}}{4 \text{ hours}} $
$ \text{Average Speed} = 500 \text{ km/hour} $
Therefore, the average speed for the duration the person is in the air is 500 km/hour.
Important Questions from Speed Time & Distance (Notes)
A and B have to travel from place P to place Q following the same route in their respective cars. A drives at $60$ kmph while B drives at $80$ kmph. Find the time taken by B to reach place Q if A takes $12$ hrs.
On a straight road, a bus is $60$ km ahead of a car running in the same direction. After $3$ hours, the car is $90$ km ahead of the bus. If the speed of the bus is $45$ km/h, then what is the speed of the car (in km/h)?
A train running at the speed of $90$ kmph crosses a $250$ m long platform in $26$ seconds. What is the length of the train (in m)?
A car covers 4 successive stretches of 3 km each at speed of 10 kmph, 20 kmph, 30 kmph and 60 kmph respectively. The average speed of the car for the entire journey is:
- A car travels a total distance L. It travels half the distance with speed $v_1$ and the other half with speed $v_2$. The average speed of the car is :
