The distance between two cities, A and B, is 250 km. A motorcyclist starts from A towards B at 6:30 a.m. at a speed of 40 km/hr. Another motorcyclist starts from B towards A at 8:30 a.m. at a speed of 50 km/hr. At what time will they cross each other?
10:23:20 a.m.
The rider from A leaves at 6:30 a.m. at 40 km/hr, so by 8:30 a.m. (2 hours later) he has already covered \(40 \times 2 = 80\) km.
At 8:30 a.m. the second rider starts from B at 50 km/hr; the remaining gap between the two riders is \(250 - 80 = 170\) km.
They approach each other, so relative speed = \(40 + 50 = 90\) km/hr. Time to meet = \(170/90 = 17/9\) hours = 1 hour 53 minutes 20 seconds.
Adding to 8:30 a.m.: meeting time = 8:30:00 + 1:53:20 = 10:23:20 a.m.
Hence, they cross each other at 10:23:20 a.m.
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