Consider length to have dimension $[L]$ and temperature to have dimension $[K]$.
The question asks us to find the dimensional formula for the coefficient of linear expansion, denoted by $\alpha$. We are given the relationship that describes the change in length $(\Delta L)$ of a material based on its original length $(L_0)$, the coefficient of linear expansion $(\alpha)$, and the change in temperature $(\Delta T)$. The formula provided is:
$ \Delta L = L_0 \alpha \Delta T $
To find the dimensions of $\alpha$, we need to understand the dimensions of the other quantities involved.
We are given the following information about the dimensions:
We can rearrange the given formula to solve for $\alpha$:
$ \alpha = \frac{\Delta L}{L_0 \Delta T} $
Now, let's substitute the dimensions of each term into this equation. Let $[\alpha]$ represent the dimensional formula of $\alpha$.
The dimensional formula for the coefficient of linear expansion $(\alpha)$ is therefore $[M^0 L^0 T^0 K^{-1}]$. This indicates that $\alpha$ is independent of mass, length, and time, but depends inversely on temperature.
Given that the energy stored in an inductor is expressed as $U_L = \frac{1}{2}LI^2$ and the power dissipated in a resistor is $P = I^2R$, where $L$ is inductance, $R$ is resistance, and $I$ is current, determine the dimension of the ratio $\frac{L}{R}$.
The dimensions of energy are:
If force $[F]$, acceleration $[A]$ and time $[T]$ are chosen as the fundamental physical quantities. Find the dimensions of pressure.