If the simple interest for 2 years is Rs. 1440, what is the rate of interest ?
This problem involves calculating the rate of interest given the difference between compound interest (CI) and simple interest (SI) over two years, and the SI amount for the same period.
We are given:
First, let's find the Simple Interest for one year:
SI for 1 year = $\frac{\text{SI for 2 years}}{2}$
SI for 1 year = $\frac{1440}{2} = \text{Rs. } 720$
The difference between CI and SI for 2 years is equal to the interest charged on the first year's SI for the second year. The formula relating the difference, SI for one year, and the rate (R) is:
Difference = SI for 1 year $\times \frac{R}{100}$
Now, substitute the known values into the formula:
Rs. 60 = Rs. 720 $\times \frac{R}{100}$
To find the rate R, rearrange the equation:
\frac{R}{100} = \frac{60}{720}
\frac{R}{100} = \frac{1}{12}
R = \frac{100}{12}
R = \frac{25}{3}
R = 8\frac{1}{3}\%
Therefore, the rate of interest is $8\frac{1}{3}\%$.
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