A certain sum amounts to Rs. 15,500 in 2 years at 12% p.a. simple interest. If the same sum is compounded half-yearly at 10% per annum for \(1 \frac{1}{2}\) years, what will be the amount received?
Rs. 14,470
The question involves two parts related to interest calculations. First, we need to find the original principal sum using information about simple interest. Second, we need to calculate the final amount for the same principal sum but under compound interest, specifically compounded half-yearly.
We are given the amount received after 2 years at 12% per annum simple interest. The formula for the amount (A) in simple interest is:
\(A = P + \text{SI}\)
where P is the Principal and SI is the Simple Interest.
The formula for Simple Interest is:
\(\text{SI} = \frac{P \times R \times T}{100}\)
where R is the rate of interest per annum and T is the time in years.
Substituting the SI formula into the Amount formula:
\(A = P + \frac{P \times R \times T}{100}\)
\(A = P \left(1 + \frac{R \times T}{100}\right)\)
We are given:
Now, let's plug these values into the formula to find the Principal (P):
\(15500 = P \left(1 + \frac{12 \times 2}{100}\right)\)
\(15500 = P \left(1 + \frac{24}{100}\right)\)
\(15500 = P \left(1 + 0.24\right)\)
\(15500 = P \times 1.24\)
To find P, we rearrange the equation:
\(P = \frac{15500}{1.24}\)
\(P = 12500\)
So, the principal sum is Rs. 12,500.
Now we need to calculate the amount for the principal sum P = Rs. 12,500 under compound interest. The conditions are:
When interest is compounded half-yearly, we need to adjust the rate and the time period.
The formula for the amount (A) with compound interest is:
\(A = P \left(1 + \frac{R'}{100}\right)^n\)
Plugging in the values:
\(A = 12500 \left(1 + \frac{5}{100}\right)^3\)
\(A = 12500 \left(1 + 0.05\right)^3\)
\(A = 12500 \left(1.05\right)^3\)
Calculate \((1.05)^3\):
\((1.05)^1 = 1.05\)
\((1.05)^2 = 1.05 \times 1.05 = 1.1025\)
\((1.05)^3 = 1.1025 \times 1.05 = 1.157625\)
Now, substitute this back into the amount formula:
\(A = 12500 \times 1.157625\)
\(A = 14470.3125\)
Rounding the amount to the nearest rupee, we get Rs. 14,470.
Therefore, the amount received after \(1 \frac{1}{2}\) years compounded half-yearly at 10% per annum will be approximately Rs. 14,470.
| Concept | Formula | Notes |
|---|---|---|
| Simple Interest (SI) | \(SI = \frac{P \times R \times T}{100}\) | R = annual rate, T = years |
| Simple Interest Amount | \(A = P \left(1 + \frac{R \times T}{100}\right)\) | A = Amount, P = Principal |
| Compound Interest Amount (Annual) | \(A = P \left(1 + \frac{R}{100}\right)^T\) | R = annual rate, T = years |
| Compound Interest Amount (Half-yearly) | \(A = P \left(1 + \frac{R/2}{100}\right)^{2T}\) | R = annual rate, T = years |
| Compound Interest Amount (General) | \(A = P \left(1 + \frac{R'}{100}\right)^n\) | R' = Rate per period, n = Number of periods |
Simple Interest: In simple interest, the interest is calculated only on the initial principal amount for the entire duration. The interest earned does not get added back to the principal for calculating future interest.
Compound Interest: In compound interest, the interest earned in each period is added to the principal for calculating the interest in the next period. This leads to earning interest on interest, which results in a higher total amount compared to simple interest over the same period and rate (assuming rate > 0).
Compounding Frequency: The frequency at which interest is compounded affects the final amount. Common frequencies include:
Higher compounding frequency generally leads to a slightly higher amount for the same annual rate and time period, due to the effect of earning interest on interest more frequently.
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