The difference in compound interest on a certain sum at 10% p.a. for one year, when the interest is compounded half-yearly and yearly, is Rs. 88.80. What is the simple interest on the same sum for \(1\frac{2}{3}\) years at the same rate?
Rs. 5,920
The question asks us to find the simple interest on a certain sum for a specific time and rate, given information about the difference in compound interest calculation methods for one year on the same sum and rate. We are given the annual interest rate, the time period for the interest difference calculation, the difference amount, and the time period for which simple interest needs to be calculated.
Let's break down the information provided:
Our first step is to find the principal sum (P) using the compound interest information. Once we have P, we can calculate the simple interest for \(1\frac{2}{3}\) years at 10% p.a.
For one year at 10% p.a.:
Let P be the principal sum.
CI compounded Yearly for 1 year:
The amount after 1 year is given by the formula: \(A = P(1 + \frac{R}{100})^T\)
Here, R = 10%, T = 1 year.
\(A_{\text{yearly}} = P(1 + \frac{10}{100})^1 = P(1 + 0.1)^1 = P(1.1)\)
The compound interest is \(CI_{\text{yearly}} = A_{\text{yearly}} - P = 1.1P - P = 0.1P\)
CI compounded Half-yearly for 1 year:
The rate per half-year is \(R' = \frac{10\%}{2} = 5\%\). The number of periods in 1 year is \(n = 1 \times 2 = 2\).
The amount after 1 year is given by the formula: \(A = P(1 + \frac{R'}{100})^n\)
\(A_{\text{half-yearly}} = P(1 + \frac{5}{100})^2 = P(1 + 0.05)^2 = P(1.05)^2\)
\(A_{\text{half-yearly}} = P(1.1025)\)
The compound interest is \(CI_{\text{half-yearly}} = A_{\text{half-yearly}} - P = 1.1025P - P = 0.1025P\)
The difference between the two compound interests is given as Rs. 88.80.
\(CI_{\text{half-yearly}} - CI_{\text{yearly}} = 88.80\)
\(0.1025P - 0.1P = 88.80\)
\(0.0025P = 88.80\)
To find P, we divide 88.80 by 0.0025:
\(P = \frac{88.80}{0.0025} = \frac{88.80}{\frac{25}{10000}}\)
\(P = 88.80 \times \frac{10000}{25} = 88.80 \times 400\)
\(P = 35520\)
So, the principal sum is Rs. 35,520.
Now we need to calculate the simple interest on the sum P = Rs. 35,520 for \(1\frac{2}{3}\) years at the same rate of 10% p.a.
The formula for Simple Interest is: \(SI = \frac{P \times R \times T'}{100}\)
Here, P = 35520, R = 10%, and \(T' = 1\frac{2}{3}\) years.
Convert the mixed fraction time into an improper fraction: \(1\frac{2}{3} = \frac{(1 \times 3) + 2}{3} = \frac{3 + 2}{3} = \frac{5}{3}\) years.
Now, substitute the values into the SI formula:
\(SI = \frac{35520 \times 10 \times \frac{5}{3}}{100}\)
\(SI = \frac{35520 \times 10 \times 5}{100 \times 3}\)
\(SI = \frac{35520 \times 50}{300}\)
Cancel out common factors (like 100 from numerator and denominator):
\(SI = \frac{35520 \times 50/100}{300/100} = \frac{35520 \times 0.5}{3}\)
Alternatively, cancel out 100 directly:
\(SI = \frac{35520 \times 10 \times 5}{100 \times 3} = \frac{35520 \times 5}{10 \times 3} = \frac{3552 \times 5}{3}\)
Divide 3552 by 3:
\(3552 \div 3 = 1184\)
\(SI = 1184 \times 5\)
\(SI = 5920\)
The simple interest on the same sum for \(1\frac{2}{3}\) years at the same rate is Rs. 5,920.
By first using the difference in compound interest calculated yearly and half-yearly for one year, we found the principal sum. Then, we used this principal sum to calculate the simple interest for the specified time period and rate.
| Calculation Step | Result/Value |
|---|---|
| Rate (R) | 10% p.a. |
| Time for CI Difference | 1 year |
| CI Compounded Yearly (1 yr) | \(0.1P\) |
| CI Compounded Half-yearly (1 yr) | \(0.1025P\) |
| Difference in CI | \(0.0025P\) |
| Given Difference | Rs. 88.80 |
| Principal (P) | Rs. 35,520 |
| Time for SI (T') | \(1\frac{2}{3}\) years or \(\frac{5}{3}\) years |
| Rate for SI | 10% p.a. |
| Simple Interest (SI) | Rs. 5,920 |
| Concept | Formula | Description |
|---|---|---|
| Simple Interest (SI) | \(SI = \frac{P \times R \times T}{100}\) | Interest calculated only on the principal amount. |
| Compound Interest (CI) | \(A = P(1 + \frac{R}{100})^T\) \(CI = A - P\) |
Interest calculated on the principal amount and the accumulated interest from previous periods. T is the number of years, R is the annual rate. |
| CI Compounded Periodically (n times a year) | \(A = P(1 + \frac{R/n}{100})^{nT}\) \(CI = A - P\) |
Interest compounded more than once a year. R is annual rate, n is number of times compounded per year, T is number of years. |
Interest is a fee paid by a borrower of funds to the lender in return for the use of the money. It is typically calculated as a percentage of the principal sum.
Understanding the difference between simple and compound interest and how compounding frequency affects returns or costs is crucial for financial planning and analysis.
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