The problem asks for the annual rate of interest given the principal amount, the time period, and the difference between compound interest (compounded annually) and simple interest.
Given:
For a time period of 2 years, the difference between compound interest (CI) and simple interest (SI) is given by the formula:
$ \text{Difference} = P \times \left(\frac{R}{100}\right)^2 $
Where:
Substitute the given values into the formula:
$ 288 = 80000 \times \left(\frac{R}{100}\right)^2 $
$ \left(\frac{R}{100}\right)^2 = \frac{288}{80000} $
$ \left(\frac{R}{100}\right)^2 = \frac{144}{40000} $
$ \left(\frac{R}{100}\right)^2 = \frac{36}{10000} $
$ \frac{R}{100} = \sqrt{\frac{36}{10000}} $
$ \frac{R}{100} = \frac{6}{100} $
$ R = 6 $
Therefore, the rate of interest is 6% per annum.
What is the compound interest (in Rs.) at the rate of 10%, compounded annually, for 3 years on the principal which in 8 years at the rate of 12% per annum gives Rs. 4,800 as simple interest?
A certain sum amounts to Rs. 15,500 in 2 years at 12% p.a. simple interest. If the same sum is compounded half-yearly at 10% per annum for \(1 \frac{1}{2}\) years, what will be the amount received?
The difference in compound interest on a certain sum at 10% p.a. for one year, when the interest is compounded half-yearly and yearly, is Rs. 88.80. What is the simple interest on the same sum for \(1\frac{2}{3}\) years at the same rate?
A sum of Rs. 7500 amounts to Rs. 9075 at 10% p.a, interest being compounded yearly in a certain time. The simple interest (in Rs.) on the same sum for the same time and the same rate is:
A certain sum amounts to Rs.291600 in 2 years and to Rs.314928 in 3 years on compound interest compounded annually. How much will be the simple interest (in Rs.) on Rs.40000 at the same rate for 2 years?