The content of the registers are R1 = 25H, R2 = 30H and R3 = 40H. The following machine instructions are executed. PUSH{R1} PUSH{R2} PUSH{R3} POP{R1} POP{R2} POP{R3} After execution, the content of registers R1, R2, R3 are
R1 = 40H, R2 = 30H and R3 = 25H
This problem involves understanding how stack operations, specifically PUSH and POP, affect the contents of registers in a computer system. The stack operates on a Last-In, First-Out (LIFO) principle, meaning the last item pushed onto the stack is the first one to be popped off.
Before the execution of any instructions, the registers have the following initial hexadecimal values:
25H (\(R\text{1} = 25\text{H}\))30H (\(R\text{2} = 30\text{H}\))40H (\(R\text{3} = 40\text{H}\))Let's briefly define the two key stack operations involved in this problem:
We will now trace the execution of each machine instruction provided and observe the changes in the stack and register contents. For this example, we assume the stack grows "upwards," meaning new elements are added to the logical "top" of the stack.
| Instruction | Stack Content (Bottom \(\to\) Top) | R1 Content | R2 Content | R3 Content |
|---|---|---|---|---|
| Initial State | Empty | \(25\text{H}\) | \(30\text{H}\) | \(40\text{H}\) |
PUSH{R1} |
\([25\text{H}]\) | \(25\text{H}\) | \(30\text{H}\) | \(40\text{H}\) |
PUSH{R2} |
\([25\text{H}, 30\text{H}]\) | \(25\text{H}\) | \(30\text{H}\) | \(40\text{H}\) |
PUSH{R3} |
\([25\text{H}, 30\text{H}, 40\text{H}]\) | \(25\text{H}\) | \(30\text{H}\) | \(40\text{H}\) |
POP{R1} |
\([25\text{H}, 30\text{H}]\) | \(40\text{H}\) | \(30\text{H}\) | \(40\text{H}\) |
POP{R2} |
\([25\text{H}]\) | \(40\text{H}\) | \(30\text{H}\) | \(40\text{H}\) |
POP{R3} |
Empty | \(40\text{H}\) | \(30\text{H}\) | \(25\text{H}\) |
Let's explain each step in detail:
PUSH{R1}: The current content of R1, which is \(25\text{H}\), is placed onto the top of the stack. The stack now contains \([25\text{H}]\). The value in R1 remains \(25\text{H}\).PUSH{R2}: The current content of R2, which is \(30\text{H}\), is pushed onto the stack. The stack now contains \([25\text{H}, 30\text{H}]\). The value \(30\text{H}\) is at the top. The value in R2 remains \(30\text{H}\).PUSH{R3}: The current content of R3, which is \(40\text{H}\), is pushed onto the stack. The stack now contains \([25\text{H}, 30\text{H}, 40\text{H}]\). The value \(40\text{H}\) is now at the very top of the stack. The value in R3 remains \(40\text{H}\).POP{R1}: The value at the current top of the stack, which is \(40\text{H}\), is retrieved (popped) and loaded into R1. The stack now becomes \([25\text{H}, 30\text{H}]\). R1's content changes to \(40\text{H}\).POP{R2}: The new value at the top of the stack, which is \(30\text{H}\), is popped off and loaded into R2. The stack now becomes \([25\text{H}]\). R2's content changes to \(30\text{H}\).POP{R3}: The last remaining value at the top of the stack, which is \(25\text{H}\), is popped off and loaded into R3. The stack becomes empty. R3's content changes to \(25\text{H}\).After all the specified machine instructions have been executed, the final contents of the registers are:
This result perfectly illustrates the Last-In, First-Out (LIFO) behavior inherent in stack operations, where the order of data retrieval (POP) is the reverse of its storage order (PUSH).
This instruction is of what type?
ADD R1, A, B
The following language uses mnemonic OP codes