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Question

A ketone on treatment with bromine in methanol gives the corresponding monobromo compound [X] having molecular formula C$_5$H$_9$BrO. The compound [X] when treated with NaOMe in MeOH produces [Y] as the major product. The spectral data for compound [X] are: $^1$H NMR: $\delta$ 1.17 (d, 6H), 3.02 (m, 1H), 4.10 (s, 2H); $^{13}$C NMR: $\delta$ 17, 37, 39, 210.

The compound [X] is

The correct answer is

Identify Compound [X] using Spectral Data

The problem asks us to identify compound [X], a monobromo ketone with molecular formula C$_5$H$_9$BrO, based on its $^1$H and $^{13}$C NMR data.

Structure Elucidation using NMR Data

Analyze the given spectral data for compound [X]:

  • Molecular Formula: C$_5$H$_9$BrO. This indicates one degree of unsaturation (likely the C=O group).
  • $^{13}$C NMR: $\delta$ 17, 37, 39, 210.
    • The signal at $\delta$ 210 ppm is characteristic of a ketone carbonyl carbon (C=O).
    • The signal at $\delta$ 17 ppm suggests methyl carbons (CH$_3$).
    • Signals at $\delta$ 37 and 39 ppm suggest aliphatic carbons (CH or CH$_2$).
    • The presence of 4 signals suggests some symmetry or overlap.
  • $^1$H NMR:
    • $\delta$ 1.17 (d, 6H): Indicates two equivalent methyl groups attached to a CH group, forming an isopropyl fragment ((CH$_3$)$_2$CH-).
    • $\delta$ 3.02 (m, 1H): Corresponds to the CH proton of the isopropyl group, adjacent to the carbonyl group.
    • $\delta$ 4.10 (s, 2H): Indicates two equivalent protons on a CH$_2$ group, adjacent to an electronegative atom (like Br) and/or the carbonyl group, and not adjacent to any other protons (hence the singlet).

Proposing the Structure of [X]

Combining the NMR data and the molecular formula:

  • The presence of (CH$_3$)$_2$CH- (3H + 1H = 4H) and a C=O group accounts for C$_3$H$_7$O.
  • The singlet at $\delta$ 4.10 (2H) suggests a -CH$_2$- group.
  • The formula requires C$_5$H$_9$BrO. We have accounted for C$_4$H$_9$O. We need one more carbon and one bromine.
  • The structure must be BrCH$_2$-CO-CH(CH$_3$)$_2$. Let's verify this structure.
    • Formula: C$_5$H$_9$BrO. Correct.
    • $^{13}$C NMR: C=O (210 ppm), CH$_3$ (17 ppm, two equivalent carbons), CH (37-39 ppm), CH$_2$Br (37-39 ppm). Fits the observed 4 signals (CH and CH$_2$Br likely overlap or are very close).
    • $^1$H NMR:
      • (CH$_3$)$_2$CH-: Doublet (6H) at 1.17 ppm, Multiplet (1H) at 3.02 ppm. Matches.
      • BrCH$_2$-CO-: Singlet (2H) at 4.10 ppm. Matches.
  • This structure corresponds to option 4.

Conclusion

The spectral data perfectly matches the structure 1-bromo-3-methylbutan-2-one (BrCH$_2$-CO-CH(CH$_3$)$_2$), which is represented by option 4.

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Important Questions from Organic Synthesis

  1. For an unambiguous single step synthesis of the following target molecule (TM), the best bond disconnection in its retrosynthetic analysis is
     

  2. The major products X and Y formed in the following reaction sequences are

  3. For the following reaction, the possible product(s) is/are

  4. The reaction(s) that yield(s) X as the major product is (are) 

  5. The major products E and F in the following reaction sequence are 

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