We need to determine the coefficient of the $x^4$ term in the expansion of the polynomial $(x - 1)^3(x – 2)^3$.
Using the binomial expansion $(a-b)^3 = a^3 - 3a^2b + 3ab^2 - b^3$: $(x - 1)^3 = x^3 - 3(x^2)(1) + 3(x)(1)^2 - 1^3$ $(x - 1)^3 = x^3 - 3x^2 + 3x - 1$
Using the same binomial expansion formula: $(x - 2)^3 = x^3 - 3(x^2)(2) + 3(x)(2)^2 - 2^3$ $(x - 2)^3 = x^3 - 6x^2 + 12x - 8$
Let $P(x) = x^3 - 3x^2 + 3x - 1$ and $Q(x) = x^3 - 6x^2 + 12x - 8$. We multiply $P(x)$ by $Q(x)$. To find the $x^4$ term, we identify pairs of terms, one from each polynomial, whose powers sum to 4:
The total coefficient for the $x^4$ term is the sum of the coefficients found in Step 3: $12 + 18 + 3 = 33$
The coefficient of $x^4$ in the polynomial $(x - 1)^3(x – 2)^3$ is 33.
Given $f(x, y) = x^2 - 2xy + y^2$
The complete contour of the equation $f(x, y) = 1$ is described by the option(s) ___.