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Question

The circumference of two circles are in the ratio 5:9. Calculate the ratio of their areas.

This question was previously asked in
RRB ALP 2025 CBT 2 Mechanic Motor Vehicle Question Paper (28-Jul-2026) (Shift 1)
The correct answer is

25:81

Radius Ratio from Circumference Ratio

Let the radii of the two circles be r1 and r2, and their circumferences be C1 and C2.

The circumference formula is C = 2πr.

Given the circumference ratio:

\( \frac{C_1}{C_2} = \frac{5}{9} \)

Since the circumference (C) is directly proportional to the radius (r), the ratio of the radii is the same as the ratio of the circumferences:

\( \frac{r_1}{r_2} = \frac{C_1}{C_2} = \frac{5}{9} \)

Area Ratio Calculation

The area formula is A = πr2.

The ratio of the areas (A1 and A2) is the square of the ratio of their radii:

\( \frac{A_1}{A_2} = \frac{\pi r_1^2}{\pi r_2^2} = \left(\frac{r_1}{r_2}\right)^2 \)

Substitute the ratio of the radii (5/9) into the area formula:

\( \frac{A_1}{A_2} = \left(\frac{5}{9}\right)^2 = \frac{5^2}{9^2} = \frac{25}{81} \)

Therefore, the ratio of the areas of the two circles is 25:81.

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Important Questions from Circles

  1. If 3x + y - 5 = 0 is the equation of a chord of the circle x+ y2 - 25 = 0, then what are the coordinates of the mid-point of the chord ?

  2. What is the area of minor segment ?

  3. What is the area of major segment ?

  4. A straight line x = y + 2 touches the circle 4(x 2+ y 2) = r 2. The value of r is

  5. If the centre of the circle passing through the origin is (3, 4), then the intercepts cut off by the circle on x-axis and y-axis respectively are

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