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Question

The circumference of a circular field is 440 m, the area of the circular field will be?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is
$15400 \text{ m}^2$

Circular Field Circumference Given

The circumference (\(C\)) of the circular field is given as 440 m.

We need to find the area (\(A\)) of this field.

  • Circumference, \(C = 440\) m.
  • Area, \(A = ?\)
  • Standard formulas: \(C = 2 \pi r\) and \(A = \pi r^2\).
  • Using \(\pi \approx \frac{22}{7}\).

Calculating the Field Area

Step 1: Determine the radius (\(r\))

From the circumference formula \(C = 2 \pi r\):

\(440 = 2 \times \frac{22}{7} \times r\)

\(440 = \frac{44}{7} r\)

Solving for \(r\) yields:

\(r = \frac{440 \times 7}{44}\)

\(r = 10 \times 7 = 70\) m

Step 2: Compute the area (\(A\))

Using the area formula \(A = \pi r^2\):

\(A = \frac{22}{7} \times (70)^2\)

\(A = \frac{22}{7} \times 4900\)

Simplifying:

\(A = 22 \times 700 = 15400\) m\(^2\)

Circular Field Area Result

The calculated area of the circular field is $15400$ m\(^2\).

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Important Questions from Circles

  1. If 3x + y - 5 = 0 is the equation of a chord of the circle x+ y2 - 25 = 0, then what are the coordinates of the mid-point of the chord ?

  2. What is the area of minor segment ?

  3. What is the area of major segment ?

  4. A straight line x = y + 2 touches the circle 4(x 2+ y 2) = r 2. The value of r is

  5. If the centre of the circle passing through the origin is (3, 4), then the intercepts cut off by the circle on x-axis and y-axis respectively are

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