The radius of the circle is given as $r = 21$ cm.
The formula for the circumference ($C$) of a circle is $C = 2 \pi r$. Using the approximation $\pi \approx \frac{22}{7}$, we calculate the circumference:
$C = 2 \times \frac{22}{7} \times 21 \text{ cm}$
$C = 2 \times 22 \times 3 \text{ cm}$
$C = 132 \text{ cm}$
The problem states that the circumference of the circle equals the perimeter of an equilateral triangle.
The perimeter ($P$) of an equilateral triangle with side length $s$ is $P = 3s$.
Equating the circumference and the perimeter:
$C = P$
$132 \text{ cm} = 3s$
To find the side length $s$, divide the perimeter by 3:
$s = \frac{132 \text{ cm}}{3}$
$s = 44 \text{ cm}$
The length of the side of the equilateral triangle is 44 cm.
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