The catalytic efficiency of an enzyme is a measure of how efficiently an enzyme converts a substrate into a product. It is defined by the ratio of two key kinetic parameters: the catalytic constant (\( k_{cat} \)) and the Michaelis constant (\( K_m \)). Mathematically, it is expressed as:
\(\frac{k_{cat}}{K_m}\)
Let's understand why this particular ratio is used to define the catalytic efficiency:
The ratio \(\frac{k_{cat}}{K_m}\) effectively combines these two properties to determine how well an enzyme functions under conditions of low substrate concentration, thereby providing a measure of catalytic efficiency.
Now, let's examine the options to justify the correct answer:
Thus, the expression that defines catalytic efficiency is \(\frac{k_{cat}}{K_m}\), which is why the correct answer is this option.
Within the Michaelis-Menten framework, the ratio of $v_0/V_{max}$
when $[S] = 20 \times K_m$ is _________.
(Round off to two decimal places)
The enzyme $\alpha$-amylase used in starch hydrolysis has an affinity constant ($K_m$) value of $0.005$ M. To achieve one-fourth of the maximum rate of hydrolysis, the required starch concentration in mM (rounded off to two decimal places) is____.
An enzymatic reaction exhibits Michaelis-Menten kinetics. For this reaction, on doubling the concentration of enzyme while maintaining [S] >> [$E_o$],