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Question

You are characterizing a new enzyme isolated and purified in the laboratory. If the maximum velocity of the enzyme is $1800 \text{ } \mu moles \text{ L}^{-1}  \text{min}^{-1}$ and the total concentration of the enzyme in the reaction mixture is $1.5 \mu \text{M}$, then the turnover number of the enzyme is _______ $\text{s}^{-1}$. (answer in integer)

Enzyme Turnover Number Calculation

The turnover number ($k_{cat}$) signifies the maximum rate at which a single enzyme molecule converts substrate into product per unit time. It is determined when the enzyme is operating at its maximum velocity ($V_{max}$) relative to the total enzyme concentration ($[E]_T$).

Enzyme Turnover Number Formula

The turnover number is calculated using the following formula:

$k_{cat} = \frac{V_{max}}{[E]_T}$

Provided Data

  • Maximum velocity, $V_{max} = 1800 \text{ } \mu \text{moles } \text{L}^{-1} \text{ min}^{-1}$
  • Total enzyme concentration, $[E]_T = 1.5 \mu \text{M}$

Step 1: Convert Units

The question requires the turnover number in $\text{s}^{-1}$. First, convert the maximum velocity ($V_{max}$) from $\text{min}^{-1}$ to $\text{s}^{-1}$.

Given that $1 \text{ min} = 60 \text{ s}$:

$V_{max} = \frac{1800 \text{ } \mu \text{moles } \text{L}^{-1}}{1 \text{ min}} \times \frac{1 \text{ min}}{60 \text{ s}} = 30 \text{ } \mu \text{moles } \text{L}^{-1} \text{ s}^{-1}$

The enzyme concentration $[E]_T$ is $1.5 \mu \text{M}$, which is equivalent to $1.5 \mu \text{moles } \text{L}^{-1}$.

Step 2: Calculate Turnover Number

Substitute the converted $V_{max}$ and the enzyme concentration $[E]_T$ into the formula:

$k_{cat} = \frac{30 \text{ } \mu \text{moles } \text{L}^{-1} \text{ s}^{-1}}{1.5 \text{ } \mu \text{moles } \text{L}^{-1}}$

$k_{cat} = 20 \text{ s}^{-1}$

Result

The calculated turnover number is 20 $\text{s}^{-1}$. The question asks for the answer as an integer.

Therefore, the turnover number is 20 $\text{s}^{-1}$.

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Important Questions from Enzyme Kinetics and Michaelis Menten Equation

  1. The catalytic efficiency of an enzyme following Michaelis-Menten kinetics is defined by
  2. You have purified an enzyme using a series of chromatographic methods. It was observed that a $10 \mu \text{  g mL}^{-1}$ of this purified enzyme converted $10 \text{ mM}$ substrate per hour at 25$^{\circ}$C and pH 7. Its specific activity is _______ $\text{IU  } \mu\text{g}^{-1}$. (rounded off to three decimal places)

  3. Within the Michaelis-Menten framework, the ratio of $v_0/V_{max}$ 

    when $[S] = 20 \times K_m$ is _________. 

    (Round off to two decimal places)

  4. The activity of lactate dehydrogenase can be measured by monitoring the following reaction: 

    Pyruvate + NADH $ \longrightarrow $ Lactate + $NAD^+$ 

    The molar extinction coefficient of NADH at 340 nm is $6220 \ M^{-1}.cm^{-1}$. $NAD^+$ does not absorb at this wavelength. In an assay, $25 \ \mu L$ of a sample of enzyme (containing $5 \ \mu g$ protein per mL) was added to a mixture of pyruvate and NADH to give a total volume of 3 mL in a cuvette of 1 cm pathlength. The rate of decrease in absorbance at 340 nm was $0.14 \ min^{-1}$. The specific activity of the enzyme will be ____________________ $ \mu mol.min^{-1}.mg^{-1}$.

  5. An enzyme (E) catalyzes the biochemical reaction $A \rightarrow B$ with $k_{cat}$ equal to $500 s^{-1}$. If the initial reaction velocity ($V_0$) is $10 \mu M.s^{-1}$ at the total enzyme concentration $[E_t]$ of 30 nM and substrate concentration $[A]$ of $40 \mu M$, the value of $K_m$ (in $\mu M$) is ________
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