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Question

The average staff salary of a company is ₹ 8000/-. A new guard and a new manager are recruited with salaries of ₹ 5000/- and ₹ 20000/-, respectively. What is the current staff strength if the new average salary is ₹ 4000/- more than that of the guard?

The correct answer is
9

Calculating New Average Salary

The problem states the new average salary is ₹ 4000/- more than that of the guard.

  • Guard's Salary = ₹ 5000/-
  • New Average Salary = Guard's Salary + ₹ 4000/-
  • New Average Salary = ₹ 5000 + ₹ 4000 = ₹ 9000/-

Setting Up the Salary Equation

Let the initial number of staff be $n$.

  • Initial Average Salary = ₹ 8000/-
  • Initial Total Salary = $8000 \times n$
  • Two new employees are added (guard and manager).
  • New Staff Strength = $n + 2$
  • Salaries of new employees = ₹ 5000 (guard) + ₹ 20000 (manager) = ₹ 25000
  • New Total Salary = Initial Total Salary + Salaries of new employees
  • New Total Salary = $8000n + 25000$
  • The new average salary is calculated as:
  • $ \text{New Average Salary} = \frac{\text{New Total Salary}}{\text{New Staff Strength}} $

Solving for Initial Staff Strength

Substitute the known values into the average salary formula:

  • $₹ 9000 = \frac{8000n + 25000}{n + 2}$
  • Multiply both sides by $(n + 2)$:
  • $ 9000(n + 2) = 8000n + 25000 $
  • Distribute and simplify:
  • $ 9000n + 18000 = 8000n + 25000 $
  • Rearrange terms to solve for $n$:
  • $ 9000n - 8000n = 25000 - 18000 $ $ 1000n = 7000 $
  • Calculate $n$:
  • $ n = \frac{7000}{1000} = 7 $
  • This value, $n=7$, represents the initial staff strength.

Determining Current Staff Strength

The question asks for the *current* staff strength after the new recruits.

  • Current Staff Strength = Initial Staff Strength ($n$) + Number of New Employees
  • Current Staff Strength = $7 + 2 = 9$
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Important Questions from Average (Notes)

  1. If the average of p numbers is $q^2$ and that of q numbers is $p^2$, then the average of (p + q) numbers is :
  2. The average of 101 consecutive odd numbers is 303. Find the largest number.
  3. For three consecutive years, the cost of a product were Rs. $134$ per litre, Rs.$268$ per litre and Rs.$335$ per litre respectively. If a common man spends an average of Rs. $14740$ per year on that product, then what is the average cost of that product per litre for the three years? (In Rs. - upto two decimals)
  4. If the average of six consecutive even numbers is 13, then the average of the next three even numbers is:
  5. Raju obtained 75 and 85 marks in mathematics and physics, respectively. Find the marks he must get in chemistry to have an average of 80 marks in all the three subjects.
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