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Question

The average of 101 consecutive odd numbers is 303. Find the largest number.

The correct answer is
403

Consecutive Odd Numbers Average Calculation

We are given 101 consecutive odd numbers with an average of 303. We need to find the largest number in this sequence.

Average of Consecutive Odd Numbers

A key property of consecutive odd numbers (or any arithmetic progression) is that their average is equal to the middle term.

  • The total count of numbers is $n = 101$.
  • Since $n$ is odd, the position of the middle number is calculated as $\frac{n+1}{2}$.
  • Position of the middle number = $\frac{101+1}{2} = \frac{102}{2} = 51^{st}$.
  • Given that the average is 303, the 51st number in the sequence is 303.

Determining the Largest Number

The sequence consists of 101 terms, so the largest number is the 101st term.

  • The middle number is the 51st term (value = 303).
  • The largest number is the 101st term.
  • The number of steps (terms) from the middle number to the largest number is $101 - 51 = 50$.
  • In a sequence of consecutive odd numbers, the difference between any two adjacent numbers is 2.
  • Therefore, the difference between the 101st term and the 51st term is $50 \times 2 = 100$.
  • Largest Number = Middle Number + Difference
  • Largest Number = $303 + 100 = 403$.

The largest number in the sequence is 403.

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Important Questions from Average (Notes)

  1. The average age of a group of boys and girls is 18 years. If the average age of boys is 20 years and that of girls is 15 years, then what is the percentage of boys in the group?
  2. The average of 13 numbers is 8. If each number is multiplied by 7, then what will the new average be:
  3. There are 78 members in group A, 22 members in group B and 34 members in group C. All the members of these groups went to a restaurant. The average amounts spent on each member of groups A, B and C are ₹136, ₹383 and ₹457, respectively. The overall average amount (in ₹) spent per member is:
  4. If the average of p numbers is $q^2$ and that of q numbers is $p^2$, then the average of (p + q) numbers is :
  5. For three consecutive years, the cost of a product were Rs. $134$ per litre, Rs.$268$ per litre and Rs.$335$ per litre respectively. If a common man spends an average of Rs. $14740$ per year on that product, then what is the average cost of that product per litre for the three years? (In Rs. - upto two decimals)
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