The area of a sector is 18π cm2, and its radius is 6 cm. What is the central angle (in radians)?
\(\pi\)
Area of a sector with central angle \(\theta\) (in radians) \(= \frac{1}{2} r^2 \theta\).
\(\frac{1}{2} \times 6^2 \times \theta = 18\pi \Rightarrow 18\theta = 18\pi\)
\(\theta = \pi\) radians (that is, 180°, a semicircle).
Hence, the central angle is \(\pi\) radians.
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