The 7-digit number 236A3B9 is divisible by 3. Find the least possible value of (A+B).
1
A number is divisible by 3 when the sum of its digits is divisible by 3.
Sum of known digits of 236A3B9: \( 2+3+6+3+9=23 \), so the digit sum is \( 23+A+B \).
The next multiple of 3 after 23 is 24, so the smallest possible value is \( A+B=24-23=1 \) (for example A = 1, B = 0).
A + B = 0 would give a digit sum of 23, which is not divisible by 3.
Hence, the least possible value of (A + B) is 1.
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select the correct answer using the code given below:
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