The sum of two numbers is 32. If one number is 5 more than twice the other, then find the smaller number.
9
Let the smaller number be \(x\). Then the other number is \(2x + 5\).
Their sum is 32, so \(x + (2x + 5) = 32\).
\(3x + 5 = 32 \Rightarrow 3x = 27 \Rightarrow x = 9\).
The larger number is \(2(9) + 5 = 23\), which is indeed greater than 9.
Hence, the smaller number is 9.
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Important Questions from Linear Equation in 2 Variable
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