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Question

Direction: Study the information given carefully and answer the question given below.

‘A # B’ means ‘A is either smaller than or equal to B.’
‘A $ B’ means ‘A is neither smaller than nor equal to B.’
‘A + B’ means ‘A is either greater than or equal to B.’
‘A @ B’ means ‘A is neither greater than nor equal to B.’
‘A * B’ means ‘A is neither greater than nor smaller than B.’

Statement: U @ V + W # Y * X; V + P $ Q

Conclusion:

I)  P # X

II)  Q @ U

III) W # X

The correct answer is Only III follow

Solving Coding Decoding Inequalities

This question involves decoding a set of symbols representing inequality relations and then evaluating given conclusions based on a statement provided in the same symbolic language.

Decoding the Symbols

Let's first understand what each symbol represents in terms of standard mathematical inequalities:

Symbol Meaning Standard Inequality
# either smaller than or equal to ≤
$ neither smaller than nor equal to (i.e., greater than) >
+ either greater than or equal to ≥
@ neither greater than nor equal to (i.e., smaller than) <
* neither greater than nor smaller than (i.e., equal to) =

Decoding the Statement

The given statement is: U @ V + W # Y * X; V + P $ Q

Let's decode each part using the standard inequality symbols:

  • U @ V means U < V
  • V + W means V ≥ W
  • W # Y means W ≤ Y
  • Y * X means Y = X
  • V + P means V ≥ P
  • P $ Q means P > Q

Combining the Statement

Now, let's combine the decoded relations into a single chain or set of relations:

From the first part: U < V ≥ W ≤ Y = X

From the second part: V ≥ P > Q

We can link these through V:

U < V ≥ W ≤ Y = X

Q < P ≤ V > U (rewriting the second part starting from Q for clarity when evaluating Conclusion II)

Evaluating the Conclusions

We will now check each conclusion based on the combined statement.

Conclusion I: P # X

Decoding this, we get P ≤ X.

From the combined statement, we have the path connecting P and X: P ≤ V ≥ W ≤ Y = X.

Tracing from P to X: P ≤ V and V ≥ W ≤ Y = X.

The relation between P and X depends on the relationship between P and W (or Y or X) via V. Since we have opposing signs (`≤` and `≥`) between P and W via V (i.e., `P ≤ V ≥ W`), a definite relation between P and W cannot be established. Therefore, a definite relation between P and X cannot be established from the given statement.

Conclusion I (P ≤ X) does not definitively follow.

Conclusion II: Q @ U

Decoding this, we get Q < U.

From the combined statement, we have the path connecting Q and U: Q < P ≤ V > U.

Tracing from Q to U: Q < P and P ≤ V and V > U.

Combining these, we get Q < P ≤ V > U. Similar to Conclusion I, there are opposing signs (`≤` and `>`) between Q and U via P and V (i.e., `P ≤ V > U`). This indicates that a definite relation between Q and U cannot be established.

For example, if Q=1, P=2, V=3, U=2.5, then Q < P ≤ V > U holds, and Q < U (1 < 2.5) holds. However, if Q=1, P=2, V=3, U=0.5, then Q < P ≤ V > U holds, but Q > U (1 > 0.5).

Conclusion II (Q < U) does not definitively follow.

Conclusion III: W # X

Decoding this, we get W ≤ X.

From the first part of the statement, we have the chain: U < V ≥ W ≤ Y = X.

Focusing on the part involving W and X: W ≤ Y = X.

Since W ≤ Y and Y = X, it directly follows that W ≤ X.

Conclusion III (W ≤ X) definitively follows from the statement.

Summary of Conclusions

  • Conclusion I (P ≤ X): Does not follow.
  • Conclusion II (Q < U): Does not follow.
  • Conclusion III (W ≤ X): Follows.

Therefore, only Conclusion III follows.

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Important Questions from Coded Inequalities

  1. In the following questions, the symbols $, #, @, % and * illustrate the following meanings.

    • P $ Q - P is not smaller than Q
    • P # Q - P is neither greater than nor equal to Q.
    • P @ Q - P is neither smaller than nor equal to Q.
    • P % Q - P not greater than Q
    • P * Q - P is neither greater than nor smaller than Q

    Statements:

    K # L, L % M, M * N, N # O

    Conclusions:

    I. K # M

    II. K * M

    III. L % O

  2. Statements:

    R @ S @ T © U © X; T $ V $ W

    Conclusions:

    I. R © X

    II. X $ W

  3. Statements:

    E # F $ G $ H; G @ I

    Conclusions:

    I. H © I

    II. E @ I

  4. Statement: S @ T $ Q + R; Q * P @ W

    Conclusion:

    I)  R # W

    II)  W $ R

  5. Statement: S @ T $ Q + R; Q * P @ W

    Conclusion:

    I)  R # W

    II)  W $ R

    III) R @ T

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