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Question

In the question two statements are given, followed by two conclusions, I and II. You have to consider the statements to be true even if it seems to be at variance from commonly known facts. You have to decide which of the given conclusions, if any, follows from the given statements.

Statements:

P = U < M < K ≤ I > N

Conclusions:

I. N ≥ K

II. I > P

The correct answer is

If only conclusion II is true

Understanding Inequality Statements in Reasoning

This question asks us to analyze a given statement involving inequalities and determine which of the provided conclusions logically follows from the statement. The statement is: $P = U < M < K \le I > N$. The conclusions are:

  • I. $N \ge K$
  • II. $I > P$

We must assume the statement is true and evaluate the conclusions based solely on the relationships defined in the statement.

Analyzing the Statement: $P = U < M < K \le I > N$

The given statement provides relationships between the variables P, U, M, K, I, and N. We can break down this compound inequality into smaller parts:

  • $P = U$
  • $U < M$
  • $M < K$
  • $K \le I$
  • $I > N$

Combining the first three, we get $P = U < M < K$. This implies $P < M$ and $M < K$. Using transitivity, $P < K$. Now, let's look at the whole chain: $P = U < M < K \le I > N$.

Evaluating Conclusion I: $N \ge K$

Conclusion I states that $N \ge K$. To check this, we need to find the relationship between N and K from the given statement $P = U < M < K \le I > N$.

The part of the statement connecting K and N is $K \le I > N$.

We have a relationship between K and I ($K \le I$) and a relationship between I and N ($I > N$). However, the relationship between I and N is with a '>' sign after I, which indicates a change in direction when moving from K to N through I. Specifically, $K \le I$ means K is less than or equal to I, and $I > N$ means I is greater than N.

From $K \le I > N$, we cannot establish a definite relationship between K and N. For example:

  • If $I=5$, $K=4$, $N=3$: Then $4 \le 5 > 3$. Here $K > N$.
  • If $I=5$, $K=4$, $N=6$: Then $4 \le 5 > 6$ is false. Let's try values that satisfy the statement $K \le I > N$. If $I=5, K=5, N=4$: Then $5 \le 5 > 4$. Here $K > N$.
  • If $I=5, K=4, N=5$: Then $4 \le 5 > 5$ is false. If $I=5, K=5, N=6$: Then $5 \le 5 > 6$ is false.
  • Consider $I=10, K=8, N=12$. $8 \le 10 > 12$ is false. Let's try values satisfying $K \le I > N$: If $I=10, K=10, N=5$: $10 \le 10 > 5$. Here $K > N$. If $I=10, K=5, N=5$: $5 \le 10 > 5$. Here $K = N$. If $I=10, K=5, N=8$: $5 \le 10 > 8$. Here $K < N$.

Since different relationships ($K > N$, $K = N$, $K < N$) are possible between K and N while satisfying $K \le I > N$, there is no definite relationship between K and N. Therefore, conclusion I ($N \ge K$) does not follow from the statement.

Evaluating Conclusion II: $I > P$

Conclusion II states that $I > P$, which is equivalent to $P < I$. To check this, we need to find the relationship between P and I from the given statement $P = U < M < K \le I > N$.

Let's trace the path from P to I using the statement: $P = U < M < K \le I$.

From $P = U < M < K$:

  • $P = U$
  • $U < M$
  • $M < K$

Combining these, we get $P < M < K$. This means $P < M$ and $M < K$. By transitivity, $P < K$.

Now, we have the relationship $P < K$ and from the statement, we also have $K \le I$.

We need to combine $P < K$ and $K \le I$.

Using the transitivity rule for inequalities: If $a < b$ and $b \le c$, then $a < c$.

Here, let $a = P$, $b = K$, and $c = I$. We have $P < K$ and $K \le I$.

Therefore, $P < I$.

Conclusion II states $I > P$, which is the same as $P < I$. Since we derived $P < I$ from the statement, Conclusion II follows from the statement.

Summary of Conclusions

  • Conclusion I ($N \ge K$): Does not follow. No definite relation between N and K can be established.
  • Conclusion II ($I > P$): Follows. From $P < K$ and $K \le I$, we get $P < I$.

Based on our analysis, only conclusion II is true.

Revision Table: Inequality Relations

Relationship 1 Relationship 2 Combined Relationship Condition
$a < b$ $b < c$ $a < c$ Consistent direction
$a \le b$ $b \le c$ $a \le c$ Consistent direction
$a < b$ $b \le c$ $a < c$ Consistent direction
$a \le b$ $b < c$ $a < c$ Consistent direction
$a < b$ $b > c$ Cannot combine Opposite direction
$a \le b$ $b \ge c$ Cannot combine Opposite direction

Additional Information: Solving Statement and Conclusion Questions

To effectively solve statement and conclusion questions based on inequalities, follow these steps:

  1. Break down the statement: Identify the individual inequality relationships between variables.
  2. Combine statements: If the statement is given in parts (e.g., $A > B$, $B \le C$), combine them into a single chain ($A > B \le C$).
  3. Analyze each conclusion: For each conclusion, trace the path between the variables mentioned in the conclusion using the combined statement.
  4. Apply transitivity rules: Use the rules of inequality transitivity ($a < b, b < c \implies a < c$; $a \le b, b \le c \implies a \le c$; $a < b, b \le c \implies a < c$; $a \le b, b < c \implies a < c$) to derive a relationship.
  5. Check for opposite signs: If the path between the variables involves inequality signs in opposite directions (like $<$ followed by $>$, or $\le$ followed by $\ge$), no definite relationship can be established.
  6. Compare derived relation with conclusion: If the derived relationship matches the conclusion exactly, the conclusion is true. If it contradicts or if no definite relationship can be established, the conclusion is false.

Remember to consider the 'equal to' part in $\le$ and $\ge$ signs carefully.

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Important Questions from Coded Inequalities

  1. In a certain code language, ‘TERRAIN’ is written as ‘VETTAIP’ and ‘TRAFFIC’ is written as ‘VTHAHIE’. How will ‘MOTOR’ be written in that language?

  2. Select the option that is related to the third word in the same way as the second word is related to the first word. (The words must be considered as meaningful English words and must not be related to each other based on the number of letters/number of consonants/vowels in the word) Pig : Piglets :: Deer : ?

  3. Statements:

    P # B $ T; R & B $ S; L % R # Q

    Conclusions:

    I. P # Q

    II. L & Q

    III. T % S

    IV. P # S

  4. Statement:

    R $ W % P; N & W # S; J % T @ N; K & T

    Conclusions:

    I. N # J

    II. P # S

    III. R @ P

    IV. W $ K

  5. Statement:

    R % X @ W; Y # Z # S; X & Z; W $ U & Y

    Conclusions:

    I. U $ X

    II. W # Y

    III. S @ R

    IV. W % Z

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