The problem requires calculating the hydraulic conductivity ($K$) of a porous medium using Darcy's Law. We are given the specific discharge ($q$), the hydraulic head difference ($\Delta h$), and the flow length ($L$).
Darcy's Law states that the specific discharge ($q$) is proportional to the hydraulic gradient ($\frac{\Delta h}{L}$) and the hydraulic conductivity ($K$). The formula is:
$q = K \frac{\Delta h}{L}$
First, ensure all units are consistent. The specific discharge is given in cm/day, while head difference and flow length are in meters. Convert specific discharge to m/day:
To find the hydraulic conductivity ($K$), rearrange Darcy's Law:
$K = q \frac{L}{\Delta h}$
Substitute the given values into the rearranged formula:
$K = (0.01 \text{ m/day}) \times \frac{20 \text{ m}}{0.5 \text{ m}}$
$K = 0.01 \times 40 \text{ m/day}$
$K = 0.4 \text{ m/day}$
The calculated hydraulic conductivity is 0.4 m/day. This value falls within the specified range.