This solution details the calculation of the coefficient of permeability ($k$) for a sand column using data from a constant-head permeability test and applying Darcy's law.
| Parameter | Symbol | Value | Unit |
| Column Height | $L$ | 40 | cm |
| Cross-sectional Area | $A$ | 25 | cm² |
| Head Loss | $h$ | 50 | cm |
| Volume of Water | $V$ | 300 | cm³ |
| Time Duration | $t$ | 120 | sec (2 minutes) |
Darcy's law describes the flow of fluid through a porous medium. The formula used to calculate the coefficient of permeability ($k$) in a constant-head test is:
$ k = \frac{V \cdot L}{A \cdot h \cdot t} $
Where:
Substitute the given values into Darcy's law formula:
$ k = \frac{300 \text{ cm³} \cdot 40 \text{ cm}}{25 \text{ cm²} \cdot 50 \text{ cm} \cdot 120 \text{ sec}} $
Calculate the numerator and denominator:
$ \text{Numerator} = 300 \times 40 = 12000 \text{ cm⁴} $
$ \text{Denominator} = 25 \times 50 \times 120 = 150000 \text{ cm³} \cdot \text{sec} $
Compute the value of $k$:
$ k = \frac{12000}{150000} \text{ cm/sec} $
$ k = 0.08 \text{ cm/sec} $
The calculated coefficient of permeability ($k$) is 0.08 cm/sec.