The cross-sectional area ($A$) of the river channel is needed to calculate the discharge rate. Given the average channel width ($W$) and average depth ($D$), the area can be calculated as:
$ A = W \times D $
Substitute the given values:
$ A = 40 \, \text{m} \times 3 \, \text{m} $
$ A = 120 \, \text{m}^2 $
The discharge rate ($Q$) is the volume of water flowing per unit time. It is calculated using the formula:
$ Q = A \times V $
Where $A$ is the cross-sectional area and $V$ is the average flow speed.
Substitute these values into the discharge formula:
$ Q = 120 \, \text{m}^2 \times 2 \, \text{m/s} $
$ Q = 240 \, \text{m}^3/\text{s} $
The discharge rate is 240 m³/s. Since the question asks for an integer value, the answer is 240.